OscarGr
Nuclear
- Mar 24, 2015
- 5
Dear all,
Here comes a rather strange question, at least to my impression!
I am currently working for a customer in Sweden, they want to implement ASME III 7000 for their nuclear applications when it comes to overpressure protection (this question is not specific to ASME III I guess, the same procedure probably holds for the other ASME-standards as well). I am myself a beginner when it comes to the methods of ASME for overpressure protection but their impression/interpretation about how you evaluate the total pressure at relieving conditions to compare with the max 10 % above Design Pressure rule is to me unfamiliar. So I would hope for your thoughts about this and if you have any experience with evaluating the 10 % of Design Pressure or other similar ASME rule for overpressure protection.
What they do is basically this:
Lets assume the following:
They have a system with a Design Pressure of 100 psig. On this system they have a relief valve with a set pressure of say 100 psig. This valve has a certified ackumulation of 10 % above Pset and a spring adjustment tolerance of 3 % of the set pressure. Furthermore lets assume that they made a calculation of inlet line pressure losses and found it to be 3 psi. Furthermore from the relief valve there is a hydrostatic pressure difference in their system from the relief valve to the lowest point in a tank which amounts to 5 psi. Then they make the following calculation:
Total pressure in lowest point of the tank = Set pressure + Ackumulation + Spring adjustment tolerance + Inlet pressure line loss + Hydrostatic pressure difference = 100 psig + 10 psi + 3 psi + 3 psi + 5 psi = 121 psi
This pressure is then way above the design pressure + 10 % = 110 psig. Therefore they would not allow this installation.
Any thoughts and comments about this method is highly appreciated! Is this the intent of the ASME code? Is this common practice?
Yours truly,
Oscar
Here comes a rather strange question, at least to my impression!
I am currently working for a customer in Sweden, they want to implement ASME III 7000 for their nuclear applications when it comes to overpressure protection (this question is not specific to ASME III I guess, the same procedure probably holds for the other ASME-standards as well). I am myself a beginner when it comes to the methods of ASME for overpressure protection but their impression/interpretation about how you evaluate the total pressure at relieving conditions to compare with the max 10 % above Design Pressure rule is to me unfamiliar. So I would hope for your thoughts about this and if you have any experience with evaluating the 10 % of Design Pressure or other similar ASME rule for overpressure protection.
What they do is basically this:
Lets assume the following:
They have a system with a Design Pressure of 100 psig. On this system they have a relief valve with a set pressure of say 100 psig. This valve has a certified ackumulation of 10 % above Pset and a spring adjustment tolerance of 3 % of the set pressure. Furthermore lets assume that they made a calculation of inlet line pressure losses and found it to be 3 psi. Furthermore from the relief valve there is a hydrostatic pressure difference in their system from the relief valve to the lowest point in a tank which amounts to 5 psi. Then they make the following calculation:
Total pressure in lowest point of the tank = Set pressure + Ackumulation + Spring adjustment tolerance + Inlet pressure line loss + Hydrostatic pressure difference = 100 psig + 10 psi + 3 psi + 3 psi + 5 psi = 121 psi
This pressure is then way above the design pressure + 10 % = 110 psig. Therefore they would not allow this installation.
Any thoughts and comments about this method is highly appreciated! Is this the intent of the ASME code? Is this common practice?
Yours truly,
Oscar