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Krey method

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have I correctly interpreted the Krey method?

I get L = 1.000 m for these conditions, not 1.0776.

Wall-600_ycdje0.png
 
Oh, yes... that is what it says (in words)...

but, from time to time the math says something else:

My choosing δ = 15[sup]o[/sup] is not just some "random" slope. Fifteen degrees is a good practical slope, about 3.7 horizontal : 1 vertical, but I picked that value, δ = ρ, to easily "stress-test" the math in the spreadsheet... and the spread sheet "flunked", it is spitting out garbage.

The Krey paper (which I posted on the referenced thread) also say:

Equation-600_lpacuk.png


which is:

Calcs-1-600_ggsd8z.png


and if that is not enough, I solved the problem the old-fashion way... analog, scaled drawing using pencil & paper, following Krey's (Figure 102) instructions:

Graph-1-600_aulmca.png
Graph-2-600_xvgu2e.png


When you start at h/3, draw a line angled "down" 15[sup]o[/sup], measure off h/10, then draw a line angled "up" 15[sup]o[/sup]... surprise... you are right back where you started... L = 1.00 m.

As a matter of fact, if you choose the "right" value, say δ = 20[sup]o[/sup]... L < 1.00m.
 
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