electricpete
Electrical
- May 4, 2001
- 16,774
I am looking at a particular large vertical open (WP2) motor with spherical roller thrust bearing on top and deep groove bearing on bottom. Distance between top and bottom bearing is approx 50"
The upper bearing takes downthrust.
The lower bearing takes upthrust.
OEM specification for endplay is not available.
I believe EASA specifies 0.005" to 0.010" endplay for vertical motors.
Do you think that 0.005" to 0.010" endplay would be ok for this motor? (assuming driven equipment has no requirement).
The endplay is of course set and checked at room temperature.
If the rotor expands more than the stator, the endplay will increase.
If the stator expands more than the rotor, the endplay will decrease
Assuming both stator and rotor have temperature coefficient of steel.
Assuming endplay set at 0.005" at room temperature
How much more would stator have to increase than rotor to lose endplay (and start loading the lower bearing):
deltaL = L * deltaT * alpha
deltaT = deltaL/(L*alpha) = 0.005"(50"*0.000007/F) = 14F
That doesn't seem like much.
It seems like typical assumption is that the rotor willl heat more than the stator, but I'm not sure if that's true under all transient conditions. What do you think?
=====================================
(2B)+(2B)' ?
The upper bearing takes downthrust.
The lower bearing takes upthrust.
OEM specification for endplay is not available.
I believe EASA specifies 0.005" to 0.010" endplay for vertical motors.
Do you think that 0.005" to 0.010" endplay would be ok for this motor? (assuming driven equipment has no requirement).
The endplay is of course set and checked at room temperature.
If the rotor expands more than the stator, the endplay will increase.
If the stator expands more than the rotor, the endplay will decrease
Assuming both stator and rotor have temperature coefficient of steel.
Assuming endplay set at 0.005" at room temperature
How much more would stator have to increase than rotor to lose endplay (and start loading the lower bearing):
deltaL = L * deltaT * alpha
deltaT = deltaL/(L*alpha) = 0.005"(50"*0.000007/F) = 14F
That doesn't seem like much.
It seems like typical assumption is that the rotor willl heat more than the stator, but I'm not sure if that's true under all transient conditions. What do you think?
=====================================
(2B)+(2B)' ?