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Leaf spring press fit

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fortjp500

Automotive
Jun 22, 2021
12
I am trying to find a formula that will determine pressure at the mating surface where the housing/spring eye is open and not welded shut into a bore. Both materials are steel. I would think it would have to incorporate perhaps a spring constant or the something similar? I could not find anything in any of the design books I own.
 
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hi fortjp500

I am not understanding exactly what you are trying to do, can you provide a sketch?
I am retired now but during my working career I used to design small leaf springs etc so I might have something that can help.

“Do not worry about your problems with mathematics, I assure you mine are far greater.” Albert Einstein
 
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20220407_084636_rvdyit.jpg
 
The formula shown would be useless as soon as one would make a cut in the outer housing as it would no longer be attached (like a leaf spring eye is). I want to calculate the mating surface pressure which I can then use to determine the stess in the outer member.
 
Hi
Right I see now what you are trying to do and yes you would need the spring stiffness for the outer ring. How big a cutout are you going to make? I would think if the cut out is very small and the inner ring O.D. Was still larger than the I.D. Of the outer ring the equations might give you a good approximate. When you were talking of leaf springs I thought you meant small thin gauge material like 0.5mm thick.

“Do not worry about your problems with mathematics, I assure you mine are far greater.” Albert Einstein
 
With a gap it is a curved beam bending problem. It is unlikely that the fitting will remain round or that there will be much different than line contact rather than any surface pressure.
 
Normally what's pressed into that open eye is a bushing with a thin outer steel sleeve with the rubber bushing inside it (bonded/molded+cured in place). The outer sleeve of the bushing assembly is not perfectly rigid and will conform to the shape of the inside of the spring eye.
 
I hadn't thought of it as a curved beam with a rectangular cross section but that would be the case for sure. If I know the inner diameter of the spring eye and the outer diameter of the bushing that will be interfering, is there a way to get to stress from there using the moment equation perhaps? Sigma internal= M/eA * (ci/ri)

I don't know the Moment that would result from an interference fit? Is this the correct thought process?
 
It is a statically indeterminate situation that has to be resolved using deflection. The spring eye will be deflected to a larger diameter, the bushing will be compressed to a smaller one ... except that it won't be uniform deflection, because the outer shell of the bushing doesn't have uniform pressure on it all the way around ... because of that gap in the leaf spring eye. And, if that bushing is the normal design (steel outer shell with rubber/urethane inside it), the bushing itself is a non-uniform construction.

Why do you need to attempt to analyse this so precisely?? You won't be able to ...
 
I would like to determine how big of a tapered solid rod of steel I could insert to open the eye up before the eye or rod would yield. I was hoping there was some theoretical answer to this that someone was familiar with.
 
The only useful equation with beams is M/I=E/R=s/y. So in your case you need to know the yield stress s, the spring thickness 2y, the Young's modules. then you get the change in curvature 1/R, at yield.


Cheers

Greg Locock


New here? Try reading these, they might help FAQ731-376
 
I get that yield stress = E * y/ neutral axis. I don't understand what y is and how it relates to diametral deflection. For example if I am installing say a 1 inch radius rod into an eye that has an undersized inside radius of say 0.975" that would be diametral interference of 0.050". If the spring wall thickness is 0.25" then that puts the neutral axis at r = thickness/Ln(outer radius/inner radius) = 1.0952". I don't understand how to determine y and it's significance.
 
You need to look at beam theory. y is the distance from the neutral axis to the extreme fibre of the section. The relevant part of that equation is just the definition of E and a bit of geometry.

Cheers

Greg Locock


New here? Try reading these, they might help FAQ731-376
 
thing is that the neutral axis shifts when the beam has a very pronounced curvature, which brings you back to curved beam theory. You can apply straight beam theory to a curved member as an approximation, but the more pronounced the curvature is the less accurate it becomes. It would basically be a curved beam with a uniformly distributed load on the inside curvature (If I've got this thing pictured correctly). It's gonna take some figuring out though.
 
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