Loss factor 1

[Fazlay]

How to derive this formula of loss factor

 

[7anoter4]

According to Neher & McGrath-Temperature and Load Capability of Cable Systems:
In practice, the load carried by a cable is rarely constant and varies according to a daily load cycle having a load factor(lf).Hence, the losses in the cable will vary according to the corresponding daily loss cycle having a loss factor (LF).
From examination of a large number of load cycles and their corresponding load and loss factor:
(LF)=0.3(lf)+0.7(lf)^2 per unit [eq.3] where:
LF=loss factor
lf=load factor

 

[7anoter4]

See:

https://www.aer.gov.au/system/files/Aurora - distribution loss factor calculation methodology.PDF

 

[jghrist]

You can't really derive the formula. It is an empirical approximation. The factors 0.15 & 0.85 or 0.3 & 0.7 add to one and can vary depending on the characteristics of the load. The way to really calculate the loss factor is to get hourly loads for a year, square each one, and find the average. The loss factor is the average load squared divided by the maximum load squared.

 

[cuky2000]

EMPIRICAL LOSS EQUATION: the coefficient H=0.15 is called the Hoebel coefficient. Also (1-H)=0.85


See below the relationship between the load factor and loss factor and a brief historical background.

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