AbdullahBajwa
Mechanical
- Jul 17, 2014
- 3
I am studying about the use of alcohols as fuels in CI engines . The energy content (LHV / HHV) of alcohols is almost half as compared to that of petro diesel . My understanding of this difference is that , in order to get the same amount of work from the same engine we would need to put in twice as much alcohol as compared to diesel .The text further goes on to say that the A/F ratio for alcohols is lower as compared to petroleum fuels because of its inherent oxygen molecules .Agreed , makes perfect sense .
What I am finding difficult to grasp is the next sentence where it says "Their(alcohols) air requirement for combustion is lower , and hence, the energy content of the mixture is almost the same........Even with the lower energy content of alcohol, engine power for the given displacement would be the same "
So , the A/F ratio is lower for alcohols . This would mean that if we use a metering system originally designed for petro fuels we would get an alcohol/air mixture which is lean according to the stoichiometric calculations using the chemical equation of alcohol combustion. Can some one please explain how this results in "the energy content of the fuels being almost the same" ? Does it have something to do with the relatively high degree of completion of the combustion process due to the abundance of available air? This has been confusing me the whole morning because we know that the maximum power/MEP for engines is obtained with relatively rich mixtures.
All help would be appreciated.
What I am finding difficult to grasp is the next sentence where it says "Their(alcohols) air requirement for combustion is lower , and hence, the energy content of the mixture is almost the same........Even with the lower energy content of alcohol, engine power for the given displacement would be the same "
So , the A/F ratio is lower for alcohols . This would mean that if we use a metering system originally designed for petro fuels we would get an alcohol/air mixture which is lean according to the stoichiometric calculations using the chemical equation of alcohol combustion. Can some one please explain how this results in "the energy content of the fuels being almost the same" ? Does it have something to do with the relatively high degree of completion of the combustion process due to the abundance of available air? This has been confusing me the whole morning because we know that the maximum power/MEP for engines is obtained with relatively rich mixtures.
All help would be appreciated.