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Maximum Unsupported Beam Length Lu 2

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BigBakwas77

Structural
Jul 7, 2016
34
Does anyone have any information about how the values of Maximum Unsupported Beam Length (Lu) is derived in the Beam Selection Table of CISC Blue Book (Handbook of Steel Construction)? I have seen some threads on Eng-Tips.com which has some formulas to calculate Lu based on AISC Imperial values which I could not replicate the answers in Metric to match the values given in the Blue Book.
 
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for example, if it can helps, in Italy we used tables similar to the attached ones. Pages 1-2 calculation according to max allowable stress (1200 or 1400 kg/cm2); pages 3-4 similar calculations but enforcing limit to max deflection (L/300 or L/500). Formulas used are shown.
Full manual available if needed
 
 https://files.engineering.com/getfile.aspx?folder=227e757c-95d8-4d98-8069-20f2a05a465f&file=steel_beam_examples.pdf
BigBakwas77, check out CSA S16 (not sure what year you're working with) cl. 13.6. The code is in the first portion of the steel handbook - the tables are there for convenience, but you should be able to replicate all of the values using the code provisions.
 
@CANPRO
Thank you for your reply. I have used Cl. 13.6 of CSA 16-09 while creating a spreadsheet for Steel Beam design. What I am looking for specifically at this stage is some sort of formula/s to determine Lu for a selected section which should match the numbers provided in the Blue Book. The following thread has such formulas to work out Lu which I am unable replicate in Metric units.

 
Well you should be able to back calculate the Mr in the table to determine the appropriate Lu, just modify your spreadsheet accordingly.

I guess my question would be why are you trying to reverse engineer the table?

If you're talking about the Lu noted in the 5th column, I believe that is back calculated for the appropriate My or Mp depending on the bending class of section.
 
The Lu provided in the book is the unsupported length at which stability governs the beam strength and you can no longer reach the full potential of the section (phi*Sx*Fy). If you want to recreate that value from the book, set your equation for the unbraced strength of the beam equal to phi*Sx*Fy and solve for L.
 
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