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metric drawing dimensioning ? 1

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byrdj

Mechanical
May 21, 2003
1,663
I have very little experaince with metric. I have a drawing that gives a clearance of

0.56 +8'

what does the ' mean? I am thinking
0.56 -0 / +0.08
would that be correct?

 
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that sure isn't standard for metric length dimensioning. angular => minutes ?
 
You better ask whoever made the drawing.


Mike Halloran
Pembroke Pines, FL, USA
 
8 minutes? feet? lol Yeah better provide more info or the drawing.
 
DUH...(palm plant to forehead)
The drawing was a scan from an old instruction book. As I cut and paste to make illustration for discussion with customer, I saw it!
I have attached the drawing and now that I know what it is, I don't know how I could have read that as 0.56 +8'

Thanks for the replys
 
 http://files.engineering.com/getfile.aspx?folder=74151596-c242-47b3-9fff-60467d34aaff&file=bearing_0.JPG
0.56 + 8.7 clearance on diameter free space

?

Still makes no sense.


Mike Halloran
Pembroke Pines, FL, USA
 
It is 0.56+0.1 the lower 0 tolerance is too close to the upper 0.1 tolerance that's make it look like the number 8.
 
Ah. Now I see the 0/0. I still think it's +0.7. Crappy lettering.


Mike Halloran
Pembroke Pines, FL, USA
 
That has to be it.
the other dimensions on the drawing were all +X, but bearings are normaly given +X/-0
I think as I copied and pasted making the illustraion, some of the clutter pixels cleared up. Or I could have been It was 3am when I first looked at the drawing.
I hope it is +0.1 as that would be a reasonable tolerance for this bearing. this is the first time I have seen drawings from this OEM.

 
It makes sense for the requirement to read 0.56(-0 +0.1).

It's a strong vindication of CAD, where the text would be much clearer and sharper.
 
Until your boss prints out a D size drawing on A size paper and faxes it. Doh!

----------------------------------------

The Help for this program was created in Windows Help format, which depends on a feature that isn't included in this version of Windows.
 
Think this is [0.56 mm +0.1/-0.0 mm]

The conversion to inches would be:
0.56 mm to in = 0.022 in
0.10 mm to in = 0.004 in

thus:
[0.022 in +0.004/-0.0 in]

The diameter of the bearing is 280 mm = 11.024 in

The clearance to diameter ratio is :
0.022/11.024 = 0.002 in clearance per in diameter

Which is pretty standard for shafts this size.

saludos.
a.
 
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