bdf5526
Electrical
- Nov 26, 2007
- 51
Hi all,
Once again I need a advice from gurus here. we need to prove the transformer differential setting to our client. Relay used to protect 2 winding trafo. Diff trip works fine when we inject only at HV winding (winding a)relay CT terminals (single pahse injection and 3 pahse injection). And it is also works exactly when inject on LV (winding b)side relay CT terminals, during our secondary injection test. During this secondary injection test we proved the tripping current as per the setting in the relay.
Trafo data as follows:
25Mva
21kv/6.7kv (winding 'a'/ winding 'b')
21kv side CT ratio= 1000:1
6.7kv side CT ratio= 2500:1
Vector Group of trafo: Dny11
HV side FLA: 687 Amp and relay Ireff = 687/1000 =0.687
LV side FLA: 2154 Amp and relay Ireff = 2154/2500= 0.861
Tripping setting for Idiff> is 0.3 x Ireff
HV side relay CT terminla injected a bit more than (0.3 x (0.687)/1) = 0.206 Amp (after vector group matching factor kompensation ) and the relay triped
LV side relay CT terminal injected a bit more than (0.3 x (0.862)/0.58) = 0.445 Amp (after vector group matching factor kompensation ) and the relay tripped.
Now the client wants to see the stability of the differential. Well we were hoping the relay will not trip if we inject value above the tripping value on both side of the HV and LV winding withe tripping current which the relay tripped. We inject 30 degree lead of current at terminal Hv side at the relay. Surprisingly the relay tripped. We do not know how we can prove this stability of the differential.
Do we need to inject 3 phase on both side with HV side 30 degree lead to prove the stability?
Do we really prove this stability? during the current injection on both side to prove teh stabiliy we injected only on phase L1. could be this is the reason?
Thanks for the explanation guys
Once again I need a advice from gurus here. we need to prove the transformer differential setting to our client. Relay used to protect 2 winding trafo. Diff trip works fine when we inject only at HV winding (winding a)relay CT terminals (single pahse injection and 3 pahse injection). And it is also works exactly when inject on LV (winding b)side relay CT terminals, during our secondary injection test. During this secondary injection test we proved the tripping current as per the setting in the relay.
Trafo data as follows:
25Mva
21kv/6.7kv (winding 'a'/ winding 'b')
21kv side CT ratio= 1000:1
6.7kv side CT ratio= 2500:1
Vector Group of trafo: Dny11
HV side FLA: 687 Amp and relay Ireff = 687/1000 =0.687
LV side FLA: 2154 Amp and relay Ireff = 2154/2500= 0.861
Tripping setting for Idiff> is 0.3 x Ireff
HV side relay CT terminla injected a bit more than (0.3 x (0.687)/1) = 0.206 Amp (after vector group matching factor kompensation ) and the relay triped
LV side relay CT terminal injected a bit more than (0.3 x (0.862)/0.58) = 0.445 Amp (after vector group matching factor kompensation ) and the relay tripped.
Now the client wants to see the stability of the differential. Well we were hoping the relay will not trip if we inject value above the tripping value on both side of the HV and LV winding withe tripping current which the relay tripped. We inject 30 degree lead of current at terminal Hv side at the relay. Surprisingly the relay tripped. We do not know how we can prove this stability of the differential.
Do we need to inject 3 phase on both side with HV side 30 degree lead to prove the stability?
Do we really prove this stability? during the current injection on both side to prove teh stabiliy we injected only on phase L1. could be this is the reason?
Thanks for the explanation guys