Settingsun
Structural
- Aug 25, 2013
- 1,513
Hi,
I'm hoping someone can clarify how Microstran uses the Elastic Critical Load analysis to determine compression effective length in its steel design module.
I have a 125*5 square hollow section truss chord (Ixx = Iyy = 5.44E6 mm4) that has a maximum axial compression of 7.73 kN in a particular load case. The elastic critical load analysis gives a buckling load factor of 55.38 for this load case. Looking at the buckling shape from the elastic critical load analysis, the buckling mode is about the Y axis (out of the truss plane) between rafters at centres that vary but a bit under 5m maximum.
I thought the design module would use an axial force of 7.73 kN * 55.38 = 428 kN to calculate an effective length of 5.01m, for both X and Y axis buckling (since Ixx = Iyy). However it's actually using Lx = 38.0m and Ly = 6.8m. The chord is about 14m long. Lx corresponds to buckling in the plane of the truss in which diagonals intersect the chord at 1.5m centres.
Because of the long effective length, the steel design module give a fail result for this chord due to low member capacity in compression. I'm struggling to understand how this could be the case since the buckling load factor was 55.38.
Appreciate your thoughts.
Edit: The load case is earthquake and the chord axial force is a little odd, going from compression to tension to compression. Could the program be averaging the axial load along the member length for calculation of effective length, then using the maximum compression for the design check? Still not sure that would explain different lengths for the X & Y axes.
I'm hoping someone can clarify how Microstran uses the Elastic Critical Load analysis to determine compression effective length in its steel design module.
I have a 125*5 square hollow section truss chord (Ixx = Iyy = 5.44E6 mm4) that has a maximum axial compression of 7.73 kN in a particular load case. The elastic critical load analysis gives a buckling load factor of 55.38 for this load case. Looking at the buckling shape from the elastic critical load analysis, the buckling mode is about the Y axis (out of the truss plane) between rafters at centres that vary but a bit under 5m maximum.
I thought the design module would use an axial force of 7.73 kN * 55.38 = 428 kN to calculate an effective length of 5.01m, for both X and Y axis buckling (since Ixx = Iyy). However it's actually using Lx = 38.0m and Ly = 6.8m. The chord is about 14m long. Lx corresponds to buckling in the plane of the truss in which diagonals intersect the chord at 1.5m centres.
Because of the long effective length, the steel design module give a fail result for this chord due to low member capacity in compression. I'm struggling to understand how this could be the case since the buckling load factor was 55.38.
Appreciate your thoughts.
Edit: The load case is earthquake and the chord axial force is a little odd, going from compression to tension to compression. Could the program be averaging the axial load along the member length for calculation of effective length, then using the maximum compression for the design check? Still not sure that would explain different lengths for the X & Y axes.