BBN75
Electrical
- Oct 21, 2018
- 1
Hello! I realize this is more of an engineer forum but I've looked all over trying to find an answer to what a motor would do if hooked up wrong. Hopefully some of the experts here know the answer as it's driving me crazy! This is for a motor on a fire suppression water pump at a large industrial plant. This was a complete system upgrade. I'm 99.9% sure I hooked this motor up as the attached 460//380V diagram shows. It's a 12 lead motor with the 4-7, 5-8, and 6-9 winding hookup and the L1-T1-T12, L2-T2-T10, and L3-T3-T11 motor lead connections. The motor was checked for proper rotation and I was told that it was correct. I wasn't present when this was done so I don't know if it barely turned or if it turned freely for a little while. It's in a very noisy environment and it wasn't noticed if the enclosed breaker did or didn't trip. A few days later, water was sent through the attached pump and the breaker kept tripping. I was told the hook up was looked at and it was hooked as L1-T1-T2, L2-T10-T12, and L3-T3-T11 connections. My question is; Would this have been a direct short with an accompanying BOOM if L1-T1-T2 and L2-T10-t12 connections were improperly did this way? Or, would the motor have even turned at all? Just curious as to what the motor reaction would have been if the wrong connections were made this way. I'm an industrial electrician with 29 years experience. Any and all input is greatly appreciated!