Oil Cooling System Help

[KoolTemp]

I am an intern and have a project that I'm supposed to go look at. I would like to get some help on here first that way I don't sound like a dumb a$$ when I talk to my boss haha. The information I have is very limited and it is as follows.

they want to cool the oil from 180F to 60F in 2 hours. they are going to run a cooling medium through plates in the oil tank for the heat removal.... that is all the info i have.


What information do I still need and more importantly what equations and design steps will help me solve this problem.

Appreciate all the help in advance.

 

[sspeare]

You probably should have posted in the Heat Transfer forum, but I'll comment anyway. Remember from Heat Transfer & Thermo the basic equation: Q = M x Cp x delta T.

Where:

Q = BTU/hour of heat transferred.
M = pounds, or lb.
Cp = specific heat at constant pressure = BTU/lb/degree F
delta T = change in fluid temperature = (180 - 60) degrees F = 120 deg F.

You say "oil." There are many different "oils", so let's just guess that the Cp of your oil is 0.43 BTU/lb/degree F. You don't say how many pounds (or gallons) are in the tank, so we can calculate what happens for one (1) gallon, assuming 7.5 lb/gallon density.

Q = [M x Cp x delta T] / [2 hours]
Q/gallon = [1 gal) x 7.5 lb/gal] x [0.43 BTU/lb/deg F] x [120 deg F] / [2 hours]
Q/gallon = 193.5 BTU/hour/gallon.

If your tank has 8,000 gallons of oil, your heat transfer is:

8,000 gal x 193.5 BTU/hr/gal = 1,548,000 BTU/hour.

Hope this helps.

 

[KoolTemp]

Thanks for your help sspeare