eguentsch
Chemical
- Jul 10, 2006
- 7
Many times I have heard people make a statement such as "In a spool with pipe and flanges, the flange will always be the weakest link with regard to MAWP".
I am wondering whether this statement is wrong or at least should be worded less general.
From ASME B31.3 I can calculate what pressure a pipe with a wall thickness t can withstand:
P = (2*S*E*t)/(D-2*y*t),
where t = t_nom(1-tol)-ca-threaded-ea
tol: manufacturing tolerance (usually 12.5/100)
ca: corosion allowance
ea: erosion allowance
As an example consider the following:
2" XS CS pipe with #600 CS flanges at 100F, 1/8"ca, no threading, no erosion allowance.
The above formula gives me an MAWP of 1132 Psig, while the flange can withstand 1480 (according to ASME B16.5 table 2, page 22)
So, I think, the above statement should be revised towards:
"In a non-corrosive, non-erosive, unthreaded pipe spool with flanges, the MAWP of the flange is always lower than the MAWP of the associated piping"
This statement is much more restrictive, as it should be.
Your input and discussion is more than welcome.
I am wondering whether this statement is wrong or at least should be worded less general.
From ASME B31.3 I can calculate what pressure a pipe with a wall thickness t can withstand:
P = (2*S*E*t)/(D-2*y*t),
where t = t_nom(1-tol)-ca-threaded-ea
tol: manufacturing tolerance (usually 12.5/100)
ca: corosion allowance
ea: erosion allowance
As an example consider the following:
2" XS CS pipe with #600 CS flanges at 100F, 1/8"ca, no threading, no erosion allowance.
The above formula gives me an MAWP of 1132 Psig, while the flange can withstand 1480 (according to ASME B16.5 table 2, page 22)
So, I think, the above statement should be revised towards:
"In a non-corrosive, non-erosive, unthreaded pipe spool with flanges, the MAWP of the flange is always lower than the MAWP of the associated piping"
This statement is much more restrictive, as it should be.
Your input and discussion is more than welcome.