mjh250473
Mechanical
- Mar 7, 2005
- 6
80% of pipeline is backfilled, remaining 20% is exposed. we use weighted values for start and end temps to give us overall DT that is used for allowable DP for the overall DT in the Shell Depp formula.
On all previous tests, as normal we see a pressure drop when temperature drops and calculate our DT as follows:
Start temp = (Tground*0.8)+(Texposed*0.2)
Start temp = (7.24*0.8)+(2.2*0.2)
Start temp = 6.232
End temp = (Tground*0.8)+(Texposed*0.2)
End temp = (7.18*0.8)+(1.6*0.2)
End temp = 6.064
DT = 0.168 Drop
The most recent test was carried out in very cold conditions and the relationship between P and T inversed on the exposed pipe. In general when the ambient got very cold so did the exposed pipe and the pressure went up. When ambient went up so did the exposed pipe and the pressure went down. Tground remains almost constant but behaves in the normal fashion (slight Tdrop for drop in pressure).
This left us concerned on how to calculate the DT and i question whether to use the same method as before. ie
Start temp = (Tground*0.8)+(Texposed*0.2)
Start temp = (7.24*0.8)+(0.73*0.2)
Start temp = 5.938
End temp = (Tground*0.8)+(Texposed*0.2)
End temp = (7.18*0.8)+(1.99*0.2)
End temp = 6.142
DT = 0.204 Gain
The effect of the Exposed pipe has caused the overall DT to be a gain, when the pressure has actually dropped (Pstart 155,465 Pend 155,380). This causes obvious problems.
Now as the inverse relationship is occuring would it be correct to say that as the exposed pipe temp increase should be used as a drop i.e.
Start temp = (Tground*0.8)+(Texposed*0.2)
Start temp = (7.24*0.8)+(0.73*0.2)
Start temp = 5.938
End temp = (Tground*0.8)+(Texposed*0.2)
End temp = (7.18*0.8)-(1.99*0.2)
End temp = 5.346
DT = 0.592 Drop
Which is preferable, but is it correct?
Thankyou in advance