NinerEng
Mechanical
- Jun 11, 2021
- 9
INTRO
Very new to gear design here so please bear with me.
I am attempting to reverse engineer a 2-stage stainless steel planetary gear set at work and am looking to verify the diametral pitch and pressure angle I have calculated.
I suspect that due to the slightly worn condition of the gears and possible inaccuracy in measurement that my calculated pitch and pressure angle could be wrong.
We are 99% sure these are English system gears and will identify them as such. However, I have found excellent metric resources and have done calculations in both English and metric.
Knowns for the gears in the planetary system:
# sun teeth = 10
# planet teeth = 13
# ring teeth = 38
# of planet gears = 3
Measured values (I have used an optical comparator to measure but the gears are slightly worn with soft edges so values may not be 100% correct):
planet outside diameter = 0.1315" (3.340mm)
sun outside diameter = 0.1535" (3.899mm)
center distance from sun to planet = 0.1290" (3.277mmm)
Condition #1 for a planetary system: Determines number of teeth in ring gear
Z[sub]c[/sub] = Z[sub]a[/sub] + 2Z[sub]b[/sub] --> Z[sub]c[/sub] = (10) + 2(13) --> Z[sub]c[/sub](theoretical) = 36
Z[sub]c[/sub](actual) = 38 --> Therefore profile shift must be present
Condition #2 for a planetary system: Verifies if equal center distance of planets is valid
(Z[sub]a[/sub] + Z[sub]c[/sub])/N = Integer --> (10)+(38)/(3) = 16 --> Equal center distance verified
Condition #3 for a planetary system: Verifies if planets can operate without interference
I know this is true as I am reverse engineering this system --> Non-interference verified
PLANET GEAR
Solving for Diametric Pitch:
D[sub]0[/sub] = (N+2)/P --> Therefore P = (N+2)/D[sub]0[/sub] --> P = [(13)+2)/(.1535")] --> P = 97.7
Closest "standard" P = 96 --> Diametric pitch of 96 is assumed (teeth/in)
Solving for Base Pitch:
Multiple measurements were taken using high precision digital calipers of the span between 2,3, and 4 teeth respectively.
Span of 2 Avg. = 0.0465"
Span of 3 Avg. = 0.0775"
Span of 4 Avg. = 0.1060"
Span[sub]4[/sub] - Span[sub]3[/sub] = 0.0285"
Span[sub]3[/sub] - Span[sub]2[/sub] = 0.0310"
Avg. Span Difference (Base Pitch) = 0.02975"
Solving for Pressure Angle:
BP = Π*cos(θ)/DP --> (0.2975") = Π*cos(θ)/96 --> 0.9091 = cos(θ) --> θ (pressure angle) = 24.619deg
"Standard" pressure angles are 14.5deg, 20deg, and 25deg --> Pressure angle of 25deg assumed
Undercutting Condition:
Assuming P=96 and θ = 25deg, there should be no undercut on the planet gear with 13 teeth.
SYSTEM
1) Assuming:
P[sub]planet[/sub] = P[sub]sun[/sub] --> 96
θ[sub]planet[/sub] = θ[sub]sun[/sub] --> 25deg
I found that... (formulas not shown as it was done in metric and there were quite a few of them)(Ref. KHK Gear Technical Reference Guide)
- Minimum coefficient of profile shift[sub]sun[/sub] to avoid undercut is x[sub]min[/sub] = 0.106969
- Coefficient of center distance modification (using x = 0.106969) is y[sub]min[/sub] = 0.1048149
- Center Distance[sub]min[/sub] = 3.071mm
2) Assuming:
Center distance measured = 3.277mm
I found that...
- Coefficient of center distance modification (using measured center distance)is y = 0.8847317
- Actual coefficient of profile shift[sub]sun[/sub] is x = 1.017309
OBSERVATIONS:
My main concern with these calculations is that:
1) If my measured diameters, center distances, or tooth spans are off just a tiny bit, my assumed pressure angle and diametral pitch go out the window
2) Center Distance[sub]min[/sub] = 3.071mm (0.1209"), giving x = 0.106969
Center Distance[sub]measured[/sub] = 3.277mm (0.1290"), giving x = 1.017309
Center Distance[sub]measured[/sub] - Center Distance[sub]min[/sub] = 0.206mm (0.008")
This small change in center distance drastically changes my profile shift coefficient and makes me wonder if I even need to call it out on the drawing at all.
Can't I simply make a judgement call and say x=0.5 and create my specified center distance for the gears using this?
Are these numbers close enough to determine an acceptable specification for these gears?
Sorry for the long post y'all. I have tried to make it as easy to follow my train of thought as possible.
Also to you gear professionals out there, please let me know if you catch errors in assumptions I made during calculations.
Thanks for any advice or help you can offer!
Very new to gear design here so please bear with me.
I am attempting to reverse engineer a 2-stage stainless steel planetary gear set at work and am looking to verify the diametral pitch and pressure angle I have calculated.
I suspect that due to the slightly worn condition of the gears and possible inaccuracy in measurement that my calculated pitch and pressure angle could be wrong.
We are 99% sure these are English system gears and will identify them as such. However, I have found excellent metric resources and have done calculations in both English and metric.
Knowns for the gears in the planetary system:
# sun teeth = 10
# planet teeth = 13
# ring teeth = 38
# of planet gears = 3
Measured values (I have used an optical comparator to measure but the gears are slightly worn with soft edges so values may not be 100% correct):
planet outside diameter = 0.1315" (3.340mm)
sun outside diameter = 0.1535" (3.899mm)
center distance from sun to planet = 0.1290" (3.277mmm)
Condition #1 for a planetary system: Determines number of teeth in ring gear
Z[sub]c[/sub] = Z[sub]a[/sub] + 2Z[sub]b[/sub] --> Z[sub]c[/sub] = (10) + 2(13) --> Z[sub]c[/sub](theoretical) = 36
Z[sub]c[/sub](actual) = 38 --> Therefore profile shift must be present
Condition #2 for a planetary system: Verifies if equal center distance of planets is valid
(Z[sub]a[/sub] + Z[sub]c[/sub])/N = Integer --> (10)+(38)/(3) = 16 --> Equal center distance verified
Condition #3 for a planetary system: Verifies if planets can operate without interference
I know this is true as I am reverse engineering this system --> Non-interference verified
PLANET GEAR
Solving for Diametric Pitch:
D[sub]0[/sub] = (N+2)/P --> Therefore P = (N+2)/D[sub]0[/sub] --> P = [(13)+2)/(.1535")] --> P = 97.7
Closest "standard" P = 96 --> Diametric pitch of 96 is assumed (teeth/in)
Solving for Base Pitch:
Multiple measurements were taken using high precision digital calipers of the span between 2,3, and 4 teeth respectively.
Span of 2 Avg. = 0.0465"
Span of 3 Avg. = 0.0775"
Span of 4 Avg. = 0.1060"
Span[sub]4[/sub] - Span[sub]3[/sub] = 0.0285"
Span[sub]3[/sub] - Span[sub]2[/sub] = 0.0310"
Avg. Span Difference (Base Pitch) = 0.02975"
Solving for Pressure Angle:
BP = Π*cos(θ)/DP --> (0.2975") = Π*cos(θ)/96 --> 0.9091 = cos(θ) --> θ (pressure angle) = 24.619deg
"Standard" pressure angles are 14.5deg, 20deg, and 25deg --> Pressure angle of 25deg assumed
Undercutting Condition:
Assuming P=96 and θ = 25deg, there should be no undercut on the planet gear with 13 teeth.
SYSTEM
1) Assuming:
P[sub]planet[/sub] = P[sub]sun[/sub] --> 96
θ[sub]planet[/sub] = θ[sub]sun[/sub] --> 25deg
I found that... (formulas not shown as it was done in metric and there were quite a few of them)(Ref. KHK Gear Technical Reference Guide)
- Minimum coefficient of profile shift[sub]sun[/sub] to avoid undercut is x[sub]min[/sub] = 0.106969
- Coefficient of center distance modification (using x = 0.106969) is y[sub]min[/sub] = 0.1048149
- Center Distance[sub]min[/sub] = 3.071mm
2) Assuming:
Center distance measured = 3.277mm
I found that...
- Coefficient of center distance modification (using measured center distance)is y = 0.8847317
- Actual coefficient of profile shift[sub]sun[/sub] is x = 1.017309
OBSERVATIONS:
My main concern with these calculations is that:
1) If my measured diameters, center distances, or tooth spans are off just a tiny bit, my assumed pressure angle and diametral pitch go out the window
2) Center Distance[sub]min[/sub] = 3.071mm (0.1209"), giving x = 0.106969
Center Distance[sub]measured[/sub] = 3.277mm (0.1290"), giving x = 1.017309
Center Distance[sub]measured[/sub] - Center Distance[sub]min[/sub] = 0.206mm (0.008")
This small change in center distance drastically changes my profile shift coefficient and makes me wonder if I even need to call it out on the drawing at all.
Can't I simply make a judgement call and say x=0.5 and create my specified center distance for the gears using this?
Are these numbers close enough to determine an acceptable specification for these gears?
Sorry for the long post y'all. I have tried to make it as easy to follow my train of thought as possible.
Also to you gear professionals out there, please let me know if you catch errors in assumptions I made during calculations.
Thanks for any advice or help you can offer!