Converting 0.462 m rms sinusoidal displacement at 0.38hz into g's
f = frequency = 0.38hz
w = radian frequency = 2*pi*0.38 sec^-1
Write expression for displacement d(t)
d(t)=sqrt(2)* 0.462 * sin(w*t) meters
Compute velocity v(t) as derivative of displacement d(t)
v(t) = d/dt{d(t)} = w * sqrt(2)*0.462*cos(w*t) meters
Compute acceleration a(t) as derivative of velocity v(t)
a(t) = d/dt{v(t)} = w^2 * sqrt(2)*0.462*cos(w*t) meters
Substitute w = 2*pi*0.38 sec^-1
a(t) = (2*pi*0.38 sec^-1)^2 * sqrt(2)*0.462*sin(w*t) meters
Move units to the end
a(t) = (2*pi*0.38)^2 * sqrt(2)*0.462*sin(w*t) meters/sec^2
Multiply by g*sec^2/(9.8*m^2)=1
a(t) = -(2*pi*0.38)^2 * sqrt(2)*0.462*sin(w*t) meters/sec^2 * g*sec^2/(9.8*meter)
Cancel units
a(t) = -(2*pi*0.38)^2 * sqrt(2)*0.462*sin(w*t) g / (9.8)
Rearrange all numerical factors to the front
a(t) = -[(2*pi*0.38)^2 * sqrt(2)*0.462 /9.8] * sin(w*t) g's
Solve [ ]
a(t) = -[0.38] * sin(w*t) g's
peak value of a(t) is 0.38 g's
Here is an application note on converting vibration units (handy for rotating equipment vibration conversions)
Also there are vsiour programs to perform these conversions Here is one for free:
Attached is a spreadsheet I wrote for the same purpose
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