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Propagation of boundary conditions from General static step to Perturbation step

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kushwah_dk

Mechanical
Jun 20, 2023
18
Hello Sir,
In the restart analysis if both the steps are general static steps then there is propagation of displacement boundary condition is possible from step-1 to step-2.
But if we consider step-1 as gen. static step and step-2 as a perturbation step then the propagation of displacement boundary condition is not there.
Can you please explain why it is happening?
 
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Why do you think that they don't propagate ? Here's a quote from the documentation chapter "Boundary Conditions":

By default, all boundary conditions defined in the previous general analysis step remain unchanged in the subsequent general step or in subsequent consecutive linear perturbation steps. Boundary conditions do not propagate between linear perturbation steps.
 
Yes, I have read this part from the documentation, but in my case it is not propagating from general static step to linear perturbation step.
It is propagating from one general static step to another general static step, please check the attached figure.
Why it is happening I am not understanding?
 
 https://files.engineering.com/getfile.aspx?folder=d8918306-0951-4ad6-a348-d01ba0d4f3b7&file=fig1.png
Your boundary condition is a non-zero displacement. You have to modify it if you want it to be non-zero also in the second step.
 
Yes the boundary condition is non-zero and this is automatically propagating for gen step but not for the perturbation step.
If I will modify it will not be able to apply other displacement boundary in step-2 at the same node (that I wanted to do).
Now I just wanted to ask why BCs are not propagating for perturbation step?
 
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