Pump electric motor load in process plant

[sunsentinel]

Hello,

There is a process plant with some pumps pumping fluid out of the plant
I use 2545*P*((1-eff)/eff).FUM.FLM classic pump motor heat dissipation formula from ASHRAE fundamentals handbook for these.

Now there are a lot of other pumps in this plant which only carry fluid between H/Xs, evaporators, indoor tanks etc. and fluid they pump is just transferred to the next process within the plant. Both pump and motor is indoors.
Do I use 2545*(P/eff)*FUM*FLM formula in this case?

This equation is giving me HUGE load, but hey- if it is the correct equation so be it.

Thanks!

eff=pump motor's efficiency
FUM=motor use factor
FLM=motor load factor

 

[EnergyProfessional]

heat dissipation from a motor doesn't care about where the pipes go. so the equation should be used.
I'm more concerned on how you get the efficiency since that depends on operation.

 

[sunsentinel]

Herr, thank you for reply but I do not agree with you. Motor efficiencies are estimated from ASHRAE tables..

It seems like this question has been answered before:

http://www.eng-tips.com/viewthread.cfm?qid=301417

http://www.eng-tips.com/viewthread.cfm?qid=59911

The correct equation to use in my case is

2545*(P/eff)*FUM*FLM

P=rated horsepower of pump's motor
eff=pump motor's efficiency
FUM=motor use factor
FLM=motor load factor