Reaction force from part rotation stopping 1

[kyleShropshire]

I have a cylinder rotating about its base.
When I decelerate to a stop is there a point where the ratio between the mass at the outer fibers and the center of gravity make a difference in calculating the reaction force?

The cylinder base is bolted down with four bolts and I am calculating the design factor on the bolted joint.

I was recently told this matters and want a second opinion.

 

[Snickster]

Correction

A = Angular acceleration dW/dt = d[sup]2[/sup]Theta/dt[sup]2[/sup] in radians per sec-sec

 

[SWComposites]

Just when the ratio D/d was over 2 to "double the force". - this makes no sense; if the ratio is 1.9 then the force is the same as if the ratio is 1??? But when the ratio is 2 or more, the force doubles? Huh??? Sounds like some sort of hip shooting clueless nonsense.

 

[Snickster]

Correction

Say total length of cylinder = 2 ft.

Then for D/d = 1, D = 1 ft and d = 1 ft

For D/d = 2 then D = 4/3 ft and d = 2/3 ft

So ratio of moment about the base from d = 1 to d = 2/3 is (2/3)/1 = 2/3 but shear forces at base are same.