Reaction forces on two roller supports with an free end 3

[Algirdas13]

Hey everyone,

I have a fairly simple question, but just wanted to make sure that I'm not missing something out. There is a beam that on one end is supported by two roller supports, on another end there's applied a load. I'm wondering if the reaction force R2 gonna be R2=F, and the reaction force R1 gonna be R1=R2+F?

 

[Eng16080]

With just this simple trick, you can solve the problem:
[ol 1]
[li]Sum of forces in the Y direction = 0[/li]
[li]Sum of moments about any point = 0[/li]
[/ol]

Show us your calcs after doing this if you're still not sure.

 

[rb1957]

Spoiler

R1 = 2F, R2 = F

"Hoffen wir mal, dass alles gut geht !"
General Paulus, Nov 1942, outside Stalingrad after the launch of Operation Uranus.

 

[HTURKAK]

TRUE! R2=F, and the reaction force R1 gonna be R1=2F
You can calculate with equilibrium equations ,
∑FX=0

∑FY=0

∑M r1=∑M r2=0



According to the grace of God which is given
unto me, as a wise masterbuilder, I have laid the foundation, and another buildeth thereon. . . .
I Corinthians 3:10

 

[Algirdas13]

Hey guys!

Thank you for all the comments, suggestions and answers! Nevertheless the problem seems fairly simple, for some reason it was difficult for me to believe, that roller (R2), being on other side will act against other roller (R1). After your comments there are no doubts left. Thanks!

 

[jayrod12]

I always tell people to use their pencil as a beam and for determinate structures like these, technically unstable without friction at one of the rollers but that's another discussion, the answer is usually clear at that point.

 

[BAretired]

The structure, as depicted, is unstable. For stability, one of the roller supports must be a pin.

 

[milkshakelake]

Yeah, this is unstable. In real life, this would be for a crane or something.