Continue to Site

Eng-Tips is the largest engineering community on the Internet

Intelligent Work Forums for Engineering Professionals

  • Congratulations MintJulep on being selected by the Eng-Tips community for having the most helpful posts in the forums last week. Way to Go!

Reactive power 4

Status
Not open for further replies.

Cerkit

Electrical
Jan 18, 2016
100
Hi.Can someone please help explain how it is that in a power system it is possible to have real and reactive power moving in opposite directions? Or is this just to do with nomenclature and ways of describing leading and lagging power factor?
Also how exactly does a generator exporting with a leading or lagging power factor affect how its impact on the voltage of the network, ie a lagging pf can support the voltage on a network?

Thanks
 
Replies continue below

Recommended for you

Why does voltage drop as the reactive load is increased?
 
You will see this if you draw the phasor diagrams.

Let's just model your transmission line as an inductor with an impedence of Xl*i.

Zt = Transmission line impedence = Xl*i= 1<90 deg pu. Completely reactive transmission line.

Vs = source voltage. = 1<0 deg pu for this example.

Il = load current. = 0.1<-90 deg pu for this example. A completely reactive load. Current lagging voltage by full 90 deg at 0.1 pu.

Vl = Voltage at load = Vs - Il*Zt = 1<0 - (0.1<-90)*(1<90) = 0.9 < 0 deg pu.


If you draw you out that phasor diagram for Vl = Vs-Il*Zt, what you will see is that the lagging current puts the voltage drop more inline with the source voltage resulting in a greater magnitude drop. If the load had been purely resistive, the voltage drop across the transmission line would have been 90 degree out of phase with the source voltage and the voltage drop would have been magnitudely less. Let's say that load was capacitive, like a capacitor bank, the voltage drop would be 180 degrees out of phase with the source and the voltage would actually be higher at the cap bank than at the source. The voltage drop will always be the greatest when the angle of the current is equal and opposite of the angle of the transmission line impedance. It just happens to be that transmission lines generally are very reactive. This is also why the voltage drop across a transformer depends on the power factor of the load.


To further answer your question of real and imaginary power flows, the angle differences between buses tends to be small. This allows the power flow equations to be decoupled for iterative power flow solution methods. When you decouple the equations, vars flow from high voltage to low voltage (on a pu basis) and real power flows based on voltage angle differences between buses. If you ever use do transmission studies with PSS/, Powerworld, or the like, it becomes very obvious that capacitor banks hardly impact real power flows and you need real power generation or load to change real power flows, excluding outages.


Look under 'Power-flow problem formulation' to see how the equations can be decoupled
 
Status
Not open for further replies.

Part and Inventory Search

Sponsor