Hey all, I have this problem that I need to reduce the speed of a motor from 1000 rpm to only 1 rpm. Is this possible in reality? And if there is a gearbox that does this, I want to knnow where to find it.
The existing rotary vector drive can have
a reduction ratio of 1000, by using the
involute gears for its 1st planetary drive,
and cycloid, harmonic or Ikona gears for
its 2nd planetary drive.
But I also have several questions for you:
(1) Does it require to be back-driveable?
(2) Is this a plastic gearbox or metal gearbox?
(3) What's the approximate dimension?
If it's a plastic box, I don't know at the moment
whether harmonic drive can be used.
Many thanks to you all: ivymike, tbuelna, israelkk and paulliu. About this gearbox, now I think that I will need even a bigger reduction ratio, because the motor offered to me at the moment is 500 rpm, and I need to reduce it to 0.05 rpm.
The answers to paulliu's questions is as follows:
1- No, it does not require to be back-driveable.
2- It is a metal gearbox, not a plastic one.
3- I do not have any restriction on the dimension side.
Now for a speed reduction ratio of 10,000, a recent
example I saw, employed two gearboxes with a speed
reduction ratio of 100 for each of them, and each
of which may use the harmonic gear drive, or worm-gear
drive, or involute planetary gear-drive et. al.
Two worm gear reducers one attached to the other with 100:1 ratios (usually the highest you get in commercial units) will render the 10,000:1 ratio you need your efficiency should be down to around 0.6 so if you need 60 Nm you should aim at an input of:
100Nm/10,000 = 0.01 Nm = 0.074 ft-lb input < 1 inch-lb
Which puts you at the really smallest section of speed reducers for the input side and even the secondary one can be a less than an inch in sizing. (worms speed reducers are determined by the distance between axis of the worm and wheel)
Youll find those in the Grainger catalog as sub-fractional speed reducers