Regenerative system

[Ray2]

I have a regenerative type hydraulic system. It does not quite have enough power on the extension cycle, the retraction cycle is fine. Does anyone know how I can get more power on the extension cycle, or will I have to replace the cylinders with a larger diameter rod?

Thanks,
Ray D

 

[hydtools]

If by more power you mean more force, yes you must increase the rod size. In a regenerative system, the net effective area for a push force is the rod area.

Or you could arrange a sort of sequence valve arrangement that would change from regenerative to non-regenerative mode. This would give you rapid advance that regeneration gives with a full force push that non-regeneration gives at a predetermined pressure. It's been a while since I did this for a shear, so I will have to think about it. Someone else may have the quick answer.

Ted

 

[hydtools]

Examples of regen valves with pressure sensitive changeover from regen to non-regen and their internal circuits are here:

http://www.sunhydraulics.com/PDF Files/US Line Mount/us_assm_regen.pdf

Ted

 

[budt]

What is the Cylinder Bore Diameter (Inches),

What is the Rod Diameter (Inches)?

What is your Valve flow rate in GPM? Valve Size?

What is the maximum pressure setting (PSI)?

What pressure does a Gauge read (PSI) while extending in Regeneration?

Can you post a schematic?


Bud Trinkel, Fluid Power Consultant
HYDRA-PNEU CONSULTING

 

[Ray2]

I understand more now, you can't think the rod needs to be half the diameter of the cylinder, I have to figure surface area. (duh) The cylinders I have now are 1 1/2" with a 5/8" rod, they came with the pump, so I assumed they were the right ones, ( been there before) I have a 3,000 PSI pump, 1/4" fluid lines and the flow is very low, (30 seconds to extend 32") also I have no way to measure either the flow or pressure. With this configuration I figure I only have approx. 921 lb. pressure on the extend cycle, (not enough) I would like double that. I figure the ideal cylinder would be 1.25" with a 7/8" rod that would give me approx 1800 lbs. in both direction. I don't see any cylinders out there that are this size, I smell expensive and I need three of them.

This help is really appreciated
Ray D

 

[budt]

The standard National Fluid Power Association (NFPA) cylinder 2:1 Rod Cylinder sizes shows an inch and a half bore cylinder would have a 1" Rod.

hat gives 1.767 Sq. In's. on the Blind Side, 0.7854 Sq. In's for the Rod Area and 0.9816 for the Annuls Area on the Retract side. As you can see it is not 2:1 but as close as you can get using the standard Rod Diameters offered.

Most cylinder manufacturer's catalogs show the standard and 2:1 Rod Area cylinders.

Bud Trinkel, Fluid Power Consultant
HYDRA-PNEU CONSULTING

 

[budt]

Using a Motor type Flow Divider for a Regeneration Circuit you can Double the speed of a hydraulic cylinder of any bore and rod size or even a Double Rod Cylinder or a Hydraulic Motor.

You can see circuit designs for these circuits at:

http://www.hydraulicspneumatics.com/200/eBooks/

in the Fluid Power Circuits Explained book when Chapter on Regeneration is presented. They are putting up a chapter every other month or so.

You can see brochures this and a basic training book with information on content and price here:

http://www.ifps.org/Links/Company_Links.html

Scroll down to the HYDRA-PNEU CONSULTING link to download brochures in .pdf format. You can get a free reader for .pdf files at this site.

http://www.adobe.com/products/acrobat/readstep2.html

Bud Trinkel, Fluid Power Consultant
HYDRA-PNEU CONSULTING