Trackfiend
Civil/Environmental
- Jan 10, 2008
- 128
I'm designing the riprap apron (and rock diameter size) for (4) four force main pipes that are discharging into a channel. The four pipes are spaced 1 ft. apart. Each individual pipe is 6 ft. in diameter with a flow (Q) of approximately 210 cfs. I'm using the HEC 14 publication, specifically equation D.5 from Appendix D (Fletcher & Grace). The invert of all four pipes is 13 ft. below the water surface (TW = 13 ft.) The equation is as follows:
D(50) = 0.02D(Q/D^2.5)^4/3 x (D/TW)
Where D(50) = riprap size, ft.
Q = flow, cfs
D = diameter, ft.
TW = tailwater, ft.
My only issue is that the equation (and all of the others that I run across) only account for the diameter or area of a single pipe/culvert. Is there an equation to obtain the equivalent diameter for multiple pipes so that I can use the above mentioned equation? Or is there riprap equation out there that considers both tailwater and multiple pipes?
D(50) = 0.02D(Q/D^2.5)^4/3 x (D/TW)
Where D(50) = riprap size, ft.
Q = flow, cfs
D = diameter, ft.
TW = tailwater, ft.
My only issue is that the equation (and all of the others that I run across) only account for the diameter or area of a single pipe/culvert. Is there an equation to obtain the equivalent diameter for multiple pipes so that I can use the above mentioned equation? Or is there riprap equation out there that considers both tailwater and multiple pipes?