ExRoughneck
Petroleum
- Feb 5, 2016
- 3
Hi,
Joined a new company a couple of months ago which had order a Low Pressure Riser. The given data for riser buoyancy joint (from manufacture) was that it would still have a negative uplift of 600kg. However, after my own calculation I got that it would have a uplift of 3.5MT. Which was confirmed by physical testing in water. Given the calculation mistake on the buoyancy joint I if the buoyancy joint can take the pressure. It is supposed to be submerged to 100m.
Running through Inventor simulation I am getting that the SF of 1.6, however I dont believe inventor is taking into account elastic or plastic collapse, only Von mises. Which I believe(after checking forum here,etc) would most like be the likely the scenario for thin wall pipe/cylinder with external pressure would fail.
I have done the following assumption for my;
1. neglected polyurethane foam in the buoyancy tank. Even tough the foam can take some pressure compression. I do not know the quality of the foam nor the application of the foam. therefore I have consider the buoyancy tank as filled with air.
2. I have not calculated the complete tank as full. I have assumed the tank as size of the biggest length of the ring stiffeners.
3. Tank consist of ABS material E=30*10^6
4. Parameters used. Diameter 1200mm = 47.2in, thickness 6mm = 0.23622 in, length 1243mm = 48.94in
I have then tried to calculated the critical external pressure based on the following.
A Roark formula for thin wall tubes (7th Edition - Table 15.2 - Case 19b)
q'= 0.807 * (Et^2/lr) * 4SQRT((1/(1-v^2))^3(t^2/r^2)
= 0.807 * (30*10^6 psi * 0.23622^2 in^2/ 48.9 in * 23.622 in) * 4SQRT((1/(1-0.3^2))^3(0.23622^2 in^2)/23.622^2 in^2)
= 125 psi
B Batdorf formula in A simplified method of elastic stability analysis for thin cylinder shell
pc = 0.926 * E * RT(gamma) / ((r/t)^2.5 (l/r))
= 0.926 * 30*10^6 psi * 0.75 / ((23.622in /0.23622in)^2.5 (48.9 in / 23.622 in)
= 100.6 psi
C AMSE VIII UG28 Thickness of shell and tubes under external pressure.
Using graph in section 2 subpart 3 part D I get Factor A = 4.2 *0.001 and Factor B = 6250
Pa = 4B/(3Do/t)
= 4 * 6250 /(3 * 47.2in / 0.23622 in )
= 41.7psi
Assuming that the ASME is having a SF of approximate 3 in their graphs and Batdorf is including a reduction factor of 0.75 based on experimental is collapsing on approximately 25% less than theoretical, these are almost the same.
D - DNV OS-F201 Here I get a much lower figure
Pel = (2 * E * (t/D)) / (1 - v^2)
= (2 * 30 *10 ^6psi * (0.23622in/47.2 in )) / (1 - 0.3^2)
= 8.2 psi (I get around similar using API 5C3)
E - API 5C3
Pe = 46.95 * 10^6 / [(D/t)(D/t - 1)^2}
= 46.95 * 10^6 / [(47.2in/0.23622in)(47.2in/0.23622in - 1)^2]
= 5.94 psi
The much lower figures for DNV and API is that due to the D/t range is very high (200) and out of their range?
Is it a far assumption that the riser will have a collaps pressure with external pressure around 125psi without SF? what should be the safety factor for this according to DNV-OS-F201? ALS and normal safety class?
Appreciate any assistance/guidance for the rated external pressure / water depth for this buoyancy joint.
Joined a new company a couple of months ago which had order a Low Pressure Riser. The given data for riser buoyancy joint (from manufacture) was that it would still have a negative uplift of 600kg. However, after my own calculation I got that it would have a uplift of 3.5MT. Which was confirmed by physical testing in water. Given the calculation mistake on the buoyancy joint I if the buoyancy joint can take the pressure. It is supposed to be submerged to 100m.
Running through Inventor simulation I am getting that the SF of 1.6, however I dont believe inventor is taking into account elastic or plastic collapse, only Von mises. Which I believe(after checking forum here,etc) would most like be the likely the scenario for thin wall pipe/cylinder with external pressure would fail.
I have done the following assumption for my;
1. neglected polyurethane foam in the buoyancy tank. Even tough the foam can take some pressure compression. I do not know the quality of the foam nor the application of the foam. therefore I have consider the buoyancy tank as filled with air.
2. I have not calculated the complete tank as full. I have assumed the tank as size of the biggest length of the ring stiffeners.
3. Tank consist of ABS material E=30*10^6
4. Parameters used. Diameter 1200mm = 47.2in, thickness 6mm = 0.23622 in, length 1243mm = 48.94in
I have then tried to calculated the critical external pressure based on the following.
A Roark formula for thin wall tubes (7th Edition - Table 15.2 - Case 19b)
q'= 0.807 * (Et^2/lr) * 4SQRT((1/(1-v^2))^3(t^2/r^2)
= 0.807 * (30*10^6 psi * 0.23622^2 in^2/ 48.9 in * 23.622 in) * 4SQRT((1/(1-0.3^2))^3(0.23622^2 in^2)/23.622^2 in^2)
= 125 psi
B Batdorf formula in A simplified method of elastic stability analysis for thin cylinder shell
pc = 0.926 * E * RT(gamma) / ((r/t)^2.5 (l/r))
= 0.926 * 30*10^6 psi * 0.75 / ((23.622in /0.23622in)^2.5 (48.9 in / 23.622 in)
= 100.6 psi
C AMSE VIII UG28 Thickness of shell and tubes under external pressure.
Using graph in section 2 subpart 3 part D I get Factor A = 4.2 *0.001 and Factor B = 6250
Pa = 4B/(3Do/t)
= 4 * 6250 /(3 * 47.2in / 0.23622 in )
= 41.7psi
Assuming that the ASME is having a SF of approximate 3 in their graphs and Batdorf is including a reduction factor of 0.75 based on experimental is collapsing on approximately 25% less than theoretical, these are almost the same.
D - DNV OS-F201 Here I get a much lower figure
Pel = (2 * E * (t/D)) / (1 - v^2)
= (2 * 30 *10 ^6psi * (0.23622in/47.2 in )) / (1 - 0.3^2)
= 8.2 psi (I get around similar using API 5C3)
E - API 5C3
Pe = 46.95 * 10^6 / [(D/t)(D/t - 1)^2}
= 46.95 * 10^6 / [(47.2in/0.23622in)(47.2in/0.23622in - 1)^2]
= 5.94 psi
The much lower figures for DNV and API is that due to the D/t range is very high (200) and out of their range?
Is it a far assumption that the riser will have a collaps pressure with external pressure around 125psi without SF? what should be the safety factor for this according to DNV-OS-F201? ALS and normal safety class?
Appreciate any assistance/guidance for the rated external pressure / water depth for this buoyancy joint.