jdgengineer
Structural
- Dec 1, 2011
- 747
I'm looking to see if it is at all possible to deepen an existing ridge beam by adding another beam below and then gluing and screwing them together. I understand this is unusual for wood, and I haven't done it before, but just looking to see if it is feasible by calculation. The existing wood is dry and the new we would propose to be either KD or engineered (LVL) to minimize the potential for shrinkage that could compromise the composite behavior.
The existing beam is 4.75" wide x 13.5" tall and I am looking at adding a flat 4.75" wide x 3.5" tall wood beam to the bottom of the ridge.
To determine the screws between the two pieces I am using shear flow VQ/I.
V = 4.63 kips (worst case shear at member end)
Q = A * y(bar) = 4.75"*3.5"*6.75" = 112.2 in^3
I = 1/12 b * h^3 = 1/12 *4.75 * (13.5+3.5)^3 = 1,945 in^4
VQ/I = 4.63*112.2/1945 = 267 # / in
If I were to put in (2) SDS screws @ 3" oc I would get a force per fastener of 267 #/in * 3 " / 2 screws = 401# / screw. (I don't have proper edge distance, just evaluating relative numbers).
Does this look reasonable or is this just a crazy idea? We would also add glue between the joints. For our purposes, assume the existing beam is shored to remove all existing stresses.
The existing beam is 4.75" wide x 13.5" tall and I am looking at adding a flat 4.75" wide x 3.5" tall wood beam to the bottom of the ridge.
To determine the screws between the two pieces I am using shear flow VQ/I.
V = 4.63 kips (worst case shear at member end)
Q = A * y(bar) = 4.75"*3.5"*6.75" = 112.2 in^3
I = 1/12 b * h^3 = 1/12 *4.75 * (13.5+3.5)^3 = 1,945 in^4
VQ/I = 4.63*112.2/1945 = 267 # / in
If I were to put in (2) SDS screws @ 3" oc I would get a force per fastener of 267 #/in * 3 " / 2 screws = 401# / screw. (I don't have proper edge distance, just evaluating relative numbers).
Does this look reasonable or is this just a crazy idea? We would also add glue between the joints. For our purposes, assume the existing beam is shored to remove all existing stresses.