Not having a plan of your restaurant, i have to make some assumptions and apply code values:
1. 1/3 of floor area is kitchen, 2/3 is dining. So dining area equals 1,333 sqft. Building is rectangular, roughly 30' by 66'.
2. Based on code maximum occupancy, dining should seat about 90 people.
3. 90 people at 20 cfm/per is 1800 cfm of ventilation air introduced into the dining.
4. For Providence RI weather, about 5 tons of cooling is needed to cool the ventilation air.
5. Lights (1.5 W/sqft.) and people load add another 3 tons.
6. Ceiling height is 10'. Percent of wall area that is glass is 20%. Assuming R-13 insulation in walls and R-20 in roof (code values), and clear, insulate low-e windows, envelope load add about 2 tons.
For 3 hoods at 4000 cfm each and 80% make-up, that equates to 2400 cfm make-up. The ventilation to the dining (1800 cfm) can be applied to this make-up, so only 400 cfm needs to be brought in through the kitchen unit. This equates to about 1 ton. Not knowing the heat gain of the kitchen equipment and frequency of use, I would estimate about 20% of the listed gas input btuh. (in other words, a 100,000 btuh oven would require 20,000 btuh of cooling).
In summary, for this pizzaria in Providence RI, it looks as if the dining will require a 10 ton unit. The kitchen cooling will depend on the amount/use of equipment, but if three 100,000 btuh ovens are used (constantly), a minimum of 6 tons would be needed.
Note, all of the usual disclaimers apply as I hastily did these calculations on scratch paper during my lunch break. Any load calculation should be verified by a design professional familiar with local codes and building plan.