kaspor
Electrical
- Aug 12, 2021
- 33
Hello
I am trying to calculate the size of some structural beams. Each beam will be supported on one side by a timber stud and on the other hung vertically with timber from timber joists.
I have a box with UDL of 85kg/m (or 0.84kn/m). Box dimensions are 1.4m (L) x 1m (W) x 0.5m (H).
My span for these beams are 2.2m. I would like to use 90x45 MGP10 timber.
Sketch as follows:
My calculations are as follows:
For beam bending:
Moment capacity (Mc) = [F (allowable stress) x Breadth x Depth] / 6
For 90x45 MGP10 timber F = 17 MPa (as per AS1720.1 Table H3.1), Breadth = 45mm, Depth = 90mm.
Mc = (17 x 45 x 90^2) / 6 = 1032750 N/mm or 1.032 kN/m. This is > my requirement of 0.85kN/m so the beam is adequate.
For deflection:
Deflection (D) = [5 x W (load) x L^4 (span)] / [384 x E (Youngs Modulus) x I (section modulus)]
For 90x45 MGP10 timber, E (Youngs Modulus) = 10000 MPa for MGP10 (as per AS1720.1 Table H3.1)
W (load) = 0.84 kN/m = 0.84 N/mm
L (span) = 2200mm
I (section modulus) = (Breadth x Depth^3) / 12 = (45 x 90^3) / 12 = 2.73 x 10^6 N/mm4
Hence, Deflection = [5 x 0.84 x 2200^4] / [384 x 10000 x 2.73x10^6] = 9.4mm of deflection. This is < then the maximum limit of deflection in Australia so the beam is adequate.
Each beam will be supported by a timber stud and top plate on one side. The timber stud will be fixed laterally every 1300mm within an existing wall frame.
The other side of the beam will be supported from the floor joist. A vertical 90x45 timber will be secured to the floor joists and joist hangers will be used to support each beam from the vertical timber.
Appreciate any feedback anyone has
I am trying to calculate the size of some structural beams. Each beam will be supported on one side by a timber stud and on the other hung vertically with timber from timber joists.
I have a box with UDL of 85kg/m (or 0.84kn/m). Box dimensions are 1.4m (L) x 1m (W) x 0.5m (H).
My span for these beams are 2.2m. I would like to use 90x45 MGP10 timber.
Sketch as follows:
My calculations are as follows:
For beam bending:
Moment capacity (Mc) = [F (allowable stress) x Breadth x Depth] / 6
For 90x45 MGP10 timber F = 17 MPa (as per AS1720.1 Table H3.1), Breadth = 45mm, Depth = 90mm.
Mc = (17 x 45 x 90^2) / 6 = 1032750 N/mm or 1.032 kN/m. This is > my requirement of 0.85kN/m so the beam is adequate.
For deflection:
Deflection (D) = [5 x W (load) x L^4 (span)] / [384 x E (Youngs Modulus) x I (section modulus)]
For 90x45 MGP10 timber, E (Youngs Modulus) = 10000 MPa for MGP10 (as per AS1720.1 Table H3.1)
W (load) = 0.84 kN/m = 0.84 N/mm
L (span) = 2200mm
I (section modulus) = (Breadth x Depth^3) / 12 = (45 x 90^3) / 12 = 2.73 x 10^6 N/mm4
Hence, Deflection = [5 x 0.84 x 2200^4] / [384 x 10000 x 2.73x10^6] = 9.4mm of deflection. This is < then the maximum limit of deflection in Australia so the beam is adequate.
Each beam will be supported by a timber stud and top plate on one side. The timber stud will be fixed laterally every 1300mm within an existing wall frame.
The other side of the beam will be supported from the floor joist. A vertical 90x45 timber will be secured to the floor joists and joist hangers will be used to support each beam from the vertical timber.
Appreciate any feedback anyone has