RadovanML
Industrial
- May 20, 2015
- 11
Greetings,
I work a part-time project, it is e-cigarette. I am a mechanical engineer working on the design of atomizer, sealing, airflow, practically entire unit. It's out of my area I know but I need to do sizing of heater and I am kinda stuck. Here is the problem:
A heater is round wire, winded around the cylinder (idealized) base diameter 2,7mm.
Something like this:
Battery: 3V, 10W, 0.9 Ω
Target temperature wire heater: 180C (this is what I need)
Heater:
Kantal wire diameter of 0.4mm. Resistance 0.011 Ω / mm
The total length: 146mm (this will probably be shortened)
R = 1.61 Ω
P = V ^ 2 / R = 5.59 W
Operating time 10sec.
Here is where I begin to lose myself. According to my research the following applies:
Now when I apply my values it goes like:
5.59 * 10/716 / 1.3 = 0.06C / m3 (if I'm not mistaken per cubic meter?)
But I need the temperature to the heater and not in a volume of air. I tried to share this value with my volume (heater is placed in cylinder diameter of 4 mm, height 10mm) and I got an abnormal value.
Something is missing here. So my question is what will be the temperature on the surface of the heater - wire temperature, for know battery and if the heater is in a small volume 4mm diameter 10 hegiht cylinder.
I thank in advance, any help is welcome.
I work a part-time project, it is e-cigarette. I am a mechanical engineer working on the design of atomizer, sealing, airflow, practically entire unit. It's out of my area I know but I need to do sizing of heater and I am kinda stuck. Here is the problem:
A heater is round wire, winded around the cylinder (idealized) base diameter 2,7mm.
Something like this:
Battery: 3V, 10W, 0.9 Ω
Target temperature wire heater: 180C (this is what I need)
Heater:
Kantal wire diameter of 0.4mm. Resistance 0.011 Ω / mm
The total length: 146mm (this will probably be shortened)
R = 1.61 Ω
P = V ^ 2 / R = 5.59 W
Operating time 10sec.
Here is where I begin to lose myself. According to my research the following applies:
The specific heat of air is 716 J / kg K. The density of air is 1.3 kg / m ^ third 1 watt is 1 J / sec. So.
In 60 seconds, the temperature rise of: 100 * 60/716 / 1.3 = 6.5 C
Now when I apply my values it goes like:
5.59 * 10/716 / 1.3 = 0.06C / m3 (if I'm not mistaken per cubic meter?)
But I need the temperature to the heater and not in a volume of air. I tried to share this value with my volume (heater is placed in cylinder diameter of 4 mm, height 10mm) and I got an abnormal value.
Something is missing here. So my question is what will be the temperature on the surface of the heater - wire temperature, for know battery and if the heater is in a small volume 4mm diameter 10 hegiht cylinder.
I thank in advance, any help is welcome.