cheeryble
Mechanical
- Feb 21, 2009
- 3
Hi from Chiangmai
I am getting my head around possible solar heating for a swimming pool in an apartment block.
The pool, pumps, etc, are on the 3rd floor.
The solar collector (black irrigation tubing) would be on the roof effectively the 12th floor.
So a loop is needed rising to the collector and running back down. The question is open or closed loop system?
An open system could be pumped straight up from the pool connections and would obviate need for a heat exchanger. Only one problem springs to mind.
Whilst a sealed loop would save energy as there would be weight of water on the fallside as well as the riseside, therefore only circulation pumping required, with an open loop it struck me that above the water equivalent of 30 inches of mercury, about 32 ft of water I believe, there would be a vacuum formed in both sides of the loop.
Then I imagine water being pumped up to the tipping point at the zenith. As it runs over to the fallside one imagines a suction acting on the water rising. On reflection though after 32 ft of rise there is no atmospheric pressure left to form the positive pressure on the rise side which seems like suction on the fallside.
So are my concerns right, that it may need constant pumping against 12 minus 3 floors of head to keep this system running? Or are things more complicated than I think, and is a lighter pumping load possible?
thanx Cheeryble
I am disregarding the energy needed to pump warmer and therefore lighter water downwards to displace heavier water.....that OK?
I am getting my head around possible solar heating for a swimming pool in an apartment block.
The pool, pumps, etc, are on the 3rd floor.
The solar collector (black irrigation tubing) would be on the roof effectively the 12th floor.
So a loop is needed rising to the collector and running back down. The question is open or closed loop system?
An open system could be pumped straight up from the pool connections and would obviate need for a heat exchanger. Only one problem springs to mind.
Whilst a sealed loop would save energy as there would be weight of water on the fallside as well as the riseside, therefore only circulation pumping required, with an open loop it struck me that above the water equivalent of 30 inches of mercury, about 32 ft of water I believe, there would be a vacuum formed in both sides of the loop.
Then I imagine water being pumped up to the tipping point at the zenith. As it runs over to the fallside one imagines a suction acting on the water rising. On reflection though after 32 ft of rise there is no atmospheric pressure left to form the positive pressure on the rise side which seems like suction on the fallside.
So are my concerns right, that it may need constant pumping against 12 minus 3 floors of head to keep this system running? Or are things more complicated than I think, and is a lighter pumping load possible?
thanx Cheeryble
I am disregarding the energy needed to pump warmer and therefore lighter water downwards to displace heavier water.....that OK?