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Some boffin work required

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etch

Mechanical
May 8, 2002
169
Okay this is an unusual one.

We have a casting that i want to see what happens when i impact it. Now my plan isnt complicated (just as well), but i plan to use an steel 'H' beam and drop it from a height. I want to measure simply (no need to include air resistance, wind drift and the like );

a) the velocity at impact
B) Force on impact

Now my caluclations are

Mass m = steel beam = 25kgs
Gravity g = 10 m/s-1
height h = 5 m

therefore Potential energy stored would be

Pe= m.g.h
=1250 Joules

Kenetic Energy at impact is 1/2mv2
and assuming that all Pe = Ke then.

1250 = 1/2(25)v2
= 10ms

this i think is the velocity upon impact. Any idea what that is in real money i.e Miles per hour.

Now the force upon impact i thought would just be

F=MA,

but the more i think about it, it surely depends on the dent it leaves in the casting. or at very least the height that it is dropped from.

I know i ask the strange one, but hey it keeps it intresting
 
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Also what impacts the casting. Does the I beam hit flat, a corner of the I beam.

It depends on what the casting is sittng on when it is hit.

We built a drop weight impact tester to test carbide tipped brazed tools. 20# weight in a tube. Held up by a rope. Ruler on the side to measure how far it falls. The tube kept it falling straight.

We were looking a flat impact so we a UHMW replacable botton as the impact object.

Tom
 
Your 10 m/s is right, about 22 mph.

F=MA is the right formula but the A you need is the deceleration from 10 m/s to 0. I.E. it depends on the height dropped, the depth of the dents, plus how many milliseconds it took to create the dents. I recall a thread in here somewhere that provides better insight.
 
thanks hush i knew i was on the right track. It just a simple test to see if a aluminium casting will stand up to this type of impact. The only problem i got was converting 10m/s into mph, i got a really stoopid figure.

so i take it then it would be near impossible to calculate impact if you could not accurately determin length of impact.


no matter 22 mph will do fine.
 
I'm sure there's some way to do it with strain energy or spring constants or how high the beam bounces. I just can't think of how to approach it off the top of my head.
 
Etch,

The problem is not that simple. What you have is a question of impact. In such, the force varies with the time, going from zero at the moment of contact, through a maximum, and finally back to zero. What's termed the "impulse" of the impact is the area under that curve. This is equal to the change in momentum of the falling body.

A conversion mnemonic: The nuber of keys on a piano is 88. 88 feet per second is 60 miles per hour.
 
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