Steel Strap Design 1

[Mmarquioreto]

Hi there,

I am designing some screen panels to resist the wind force of a milk tank, and I am now stuck on the Steel Straps.
I already have the force of .012 kips, and this force pressures in 1 ft^2 of my panel.
My panel is 14' wide and 18' tall. I know that to get the horizontal force on the top of panels I need to multiply the force .012kips x 9' (for the trib width). This calculation would give me a force in kip-ft of .108kip-ft.

On the other hand the vertical force on the panel is calculated by multiplying the horizontal force found in the previous step of .108 by the panel height of 18' and divide by the panel's length of 14' ie, (.108 x 18' )/ 14' = .1388. But this now gives a force in kips and I don't think I can mix match them and proceed to calculate the sum of the squares squared to get the overall force in the straps.

Can someone please help me? What am I doing wrong? Am I missing a step?

Thank you so much for all the help with this.

Best Regards,

MLT

 

[SteelPE]

A sketch might help. I think I know what you are doing but it's hard to tell.

Also, .012 kips is tiny.

 

[Mmarquioreto]

Hi SteelPE,

I was able to figure it out, but thank you so much for your help.