boo1
Mechanical
- Oct 31, 2001
- 2,129
A thread was deleted on 2x stud wall construction. To continue the discussion the following is provided.
Analyze studs for combined axial and bending loading.
Methodology
1.Determine lumber design values, Fb, F’b, Fc, F’c, E, E’
2.Determine stress from load cases.
3.Check critical buckling.
4.Use interaction equation to proportion member.
5.Check span for bending using components and cladding pressure.
Axial Load, La
*Load case: W + D + Lr will govern,
La=W + D + Lr
Bending Load, Fb
*Load case: w (MWFRS)
Fb=(w*L**2)/(8*s)
Critical column buckling stress, FcE1
FcE1=(KcE*E’)/((Le/d)**2)
Interaction equation to check member capacities for combined loading.
((fc/Fc')**2)+(fb/(Fb'(1-(fc/FcE)))lessthanequal 1.0
Component and cladding pressures
zone 4
zone 5
Using this methodology for residential homes I thought #2 2x4's (16"oc) typically acceptable to 10' in length and the 2x6's (16"oc) limit was ~12'.
Comments?
Analyze studs for combined axial and bending loading.
Methodology
1.Determine lumber design values, Fb, F’b, Fc, F’c, E, E’
2.Determine stress from load cases.
3.Check critical buckling.
4.Use interaction equation to proportion member.
5.Check span for bending using components and cladding pressure.
Axial Load, La
*Load case: W + D + Lr will govern,
La=W + D + Lr
Bending Load, Fb
*Load case: w (MWFRS)
Fb=(w*L**2)/(8*s)
Critical column buckling stress, FcE1
FcE1=(KcE*E’)/((Le/d)**2)
Interaction equation to check member capacities for combined loading.
((fc/Fc')**2)+(fb/(Fb'(1-(fc/FcE)))lessthanequal 1.0
Component and cladding pressures
zone 4
zone 5
Using this methodology for residential homes I thought #2 2x4's (16"oc) typically acceptable to 10' in length and the 2x6's (16"oc) limit was ~12'.
Comments?