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system curve 2

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Ouahmed

Mechanical
Feb 26, 2017
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TN
i want to get the system curve of a pipeline , i ask about the method,i calculate th loss for fixed flow rated and i use the formula : PDC = a * (Qv^2)to get the curve.
with
PDC is the losshead in the system
Qv is the volume flow rate

when can i use yhis formula ?
is there any other method ?
 
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I would suggest you take the time to type "calculate head loss in pipes" into google or similar, you might be surprised to see over 800,000 links.

It is a capital mistake to theorise before one has data. Insensibly one begins to twist facts to suit theories, instead of theories to suit facts. (Sherlock Holmes - A Scandal in Bohemia.)
 
Artisi:thx for your reply but i'm already calculted the total head loss in the pipeline for a fixed flow rate. i'm asking about the system's curve.
 
you calculate for various flowrates below and above the fixed flowrate, and then plot the curve from this data.
Did you actually look at any of the links to see how its done - guess not?
There are even online calculators to make your life easy.

It is a capital mistake to theorise before one has data. Insensibly one begins to twist facts to suit theories, instead of theories to suit facts. (Sherlock Holmes - A Scandal in Bohemia.)
 
I use this spreadsheet I made. It uses basic equations you can find in any fluids book. I'll sell you a copy for $1,000,000.

Curve_lt1veu.png
 
how much for a metric version or is that included in the $1M?

It is a capital mistake to theorise before one has data. Insensibly one begins to twist facts to suit theories, instead of theories to suit facts. (Sherlock Holmes - A Scandal in Bohemia.)
 
Busted! Gentlemen promotion and sales are not allowed on the Eng-Tips website.

:)

Technology is stealing American jobs. Stop visas for robots.
 
In simplistic terms

PDC = Hl + ( a * Qv^2)

Where Hl is the static head loss at zero flow or any sort of static pressure at your end point converted to head.

Also whilst pressure drop is proportional to flowrate ^2, it is not a precise curve as Re no changes.

In the example given above , Hl is about 34ft.

In low head systems something like the difference in liquid level in a tank at the end point can change your system curve enough to make a difference.


Remember - More details = better answers
Also: If you get a response it's polite to respond to it.
 
Ouahmed,

You can convert your single calculated point to a curve using the following formula:

H = [(PCD - StaticHead)/(Qv^2)] x F^2 + StaticHead

Where

H is head of fluid as a function of F
F is flow
StaticHead is your lift and/or tank pressure
PCD is head at your single calculated point
Qv is flow at your single calculated point

You can find your operating head (H) for any value of F by curve-fitting the pump curve to a 2nd order polynomial and setting the two formulas equal to each other then finding zero. Then use the quadratic equation to solve for F. Plug F back into the equation above to find the corresponding H.


I used to count sand. Now I don't count at all.
 
Well, repeat the calculation for another fixed flow rate, and keep doing it until you can make a nice graph, from which you can estimate your coefficients.





Mike Halloran
Pembroke Pines, FL, USA
 
Using Mike's method, you only need 3 points because it will be a second order polynomial. You only need to calculate 2 points because they can be mirrored about the head axis.

I used to count sand. Now I don't count at all.
 
MFJewel,
Is there a discount for multiple copies? I presume the software comes with full QA and Certificate of conformity? Do you need excel or is it a self-contained software package?
 
Ask nicely and I'll let you make all the copies that you can carry away in one day from the one I bought.

Richard Feynman's Problem Solving Algorithm
1. Write down the problem.
2. Think very hard.
3. Write down the answer.
 
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