Dzastr
Civil/Environmental
- Aug 12, 2014
- 17
Rookie PE. Here is my situation:
I have a retaining wall that will be temporarily braced to allow for backfill prior to placement of the concrete deck that will go above the wall. Once the deck is placed it will act as a diaphragm and the bracing can be removed. I need to calculate the spacing of my pipe bracing.
Our soils report provides an Equivalent Fluid Pressure of 40, 60, and 350* psf/ft for active, at-rest, and passive conditions respectively. With the wall being 9' tall, my pipe bracing will connect to the wall at an h=7'. At a 1:1 slope that gives me a brace length of 9'11". At this length my pipe braces can withstand 6000lbs.
Is my calculation process below correct?
The force of the soil will be [40(psf/ft)*(9'^2)]/2 = 1,620 lbs/ft and it will be acting at an h=3' (1/3 of the way up from the bottom)
This gives me 3'*1620(lbs/ft) = 4,860 ft-lbs/ft
The horizontal force of my wall brace will be 6000lbs*COS(45) = 4242.6lbs and it will be acting at 7' yielding 29,700 ft-lbs.
(29,700 ft-lbs) / (4,860 ft-lbs) = 6' spacing
Follow-up question, how could I include a surcharge of say 300 psf?
Thanks in advance, please let me know if i can provide any clarification. Really appreciate this, trying to increase competency here.
I have a retaining wall that will be temporarily braced to allow for backfill prior to placement of the concrete deck that will go above the wall. Once the deck is placed it will act as a diaphragm and the bracing can be removed. I need to calculate the spacing of my pipe bracing.
Our soils report provides an Equivalent Fluid Pressure of 40, 60, and 350* psf/ft for active, at-rest, and passive conditions respectively. With the wall being 9' tall, my pipe bracing will connect to the wall at an h=7'. At a 1:1 slope that gives me a brace length of 9'11". At this length my pipe braces can withstand 6000lbs.
Is my calculation process below correct?
The force of the soil will be [40(psf/ft)*(9'^2)]/2 = 1,620 lbs/ft and it will be acting at an h=3' (1/3 of the way up from the bottom)
This gives me 3'*1620(lbs/ft) = 4,860 ft-lbs/ft
The horizontal force of my wall brace will be 6000lbs*COS(45) = 4242.6lbs and it will be acting at 7' yielding 29,700 ft-lbs.
(29,700 ft-lbs) / (4,860 ft-lbs) = 6' spacing
Follow-up question, how could I include a surcharge of say 300 psf?
Thanks in advance, please let me know if i can provide any clarification. Really appreciate this, trying to increase competency here.