Thermal difference Ansys APDL

[Eng.Arg]

Hi everbody,

Please i need help by apllying an ambient temperature ΔT to my component on Ansys APDL.
it is a 3d rectangle = 40*40*60mm and i have to apply the ambient temperature difference ΔT = 125K and analyse the deformation in Z direction.
(Material : Steel, Temperatur (T0) = 0K )
more information in the picture attached.

thank you very much

 

[Erik Panos Kostson]

Here is a sample code (you would need to change the dimensions, properties, and boundary conditions), which you can use once you have changed it:

/clear
/prep7

W=1	! Width	
L=1	! Length	
TH=0.2	! Thickness

ET,1,SOLID185

MPTEMP,,,,,,,,  ! Material prop.
MPTEMP,1,0  
MPDATA,EX,1,,200E9  
MPDATA,PRXY,1,,0.3 
MPDATA,KXX,1,,51
MPDATA,ALPX,1,,0.0000115

BLOCK,0,W,0,L,0,TH,	!Define a block

ESIZE,0.05,0	! Mesh
VMESH,ALL 

!NSEL,S,LOC,X,0	! Select nodes and apply BC
!D,ALL,UX,0
!ALLSEL,ALL
!NSEL,S,LOC,X,W
!D,ALL,UX,0
ALLSEL,ALL
NSEL,S,LOC,Y,0
D,ALL,UX,0
D,ALL,UY,0
D,ALL,UZ,0
ALLSEL,ALL


BF,ALL,TEMP,150	! Applies nodal temp. of 150 on the whole body

/SOL
!*  
ANTYPE,0
TREF,0	! Ref temp is 0 here
/STATUS,SOLU
SOLVE   
FINISH

 

[Eng.Arg]

Thank you very much