CTengineer2012
Mechanical
- Apr 11, 2012
- 12
All,
Question about thermal expansion of oil seals.
I have seal with a clearance between the top and bottom at the horizontal joint of .160". This measurement was taken with the seal pushed all the way to one side as to close up the left horizontal joint and measurement of .140" taken at the right horizontal joint.
Question: how do I calculate how much this seal will grow to close up during operation of the unit. If I treat it as simply linear, I get the following:
Aluminum has a thermal growth coefficient of 12.3x10^-6 in/in F. The diameter of the seal is 17". The temperature I'm going to is roughly 400F let's say. Can I use a straight calculation for this or do I need to take into account that this is a half circle?
This is what I get treating the seal as linear:
Circumfereance of the entire seal (both halves is 53.4. Half circle would be 26.7. Therefore: .0000123 * 26.7 * 400 = .131364". Is this correct or do I need to use a different formula since this is essentially a half circle?
Question about thermal expansion of oil seals.
I have seal with a clearance between the top and bottom at the horizontal joint of .160". This measurement was taken with the seal pushed all the way to one side as to close up the left horizontal joint and measurement of .140" taken at the right horizontal joint.
Question: how do I calculate how much this seal will grow to close up during operation of the unit. If I treat it as simply linear, I get the following:
Aluminum has a thermal growth coefficient of 12.3x10^-6 in/in F. The diameter of the seal is 17". The temperature I'm going to is roughly 400F let's say. Can I use a straight calculation for this or do I need to take into account that this is a half circle?
This is what I get treating the seal as linear:
Circumfereance of the entire seal (both halves is 53.4. Half circle would be 26.7. Therefore: .0000123 * 26.7 * 400 = .131364". Is this correct or do I need to use a different formula since this is essentially a half circle?