SMOKES
Mechanical
- Apr 29, 2011
- 46
want to check my calcs for thread engagment and number of bolts need for 240 bar test of pump casing
Bolt M16 A4-80 55mm long no shank
UTS = 800Mpa (not sure of)
UYS = 600Mpa (not sure of)
Shear ratio is 0.75 (not sure if it should be 0.7)
UTSh * 0.75 = 600Mpa
Stress Area of bolt = 156.67mm calculated
Tapped hole CF8M cast 30mm
UTS = 485MPa (known data)
UYS = 205MPa (known data)
Shear ratio =0 .75 (not sure about ratio)
UTS * 0.75
UTSh = 363.75Mpa
Minimum Length Of engagement = UTSh of bolt *0.8* Normal diameterof bolt/UTsh of tapped hole
= 600*0.8*16/363.75 = 21.2mm
Nasa Pull out load of thread
Pullout load = pi()*Min Minor diameter of thread *UTShtapped hole* Length of engagement/3
Min Minor diamet of thread = 13.872mm
= pi()*13.872*363.75* 21.2mm/3
Pullout load =112.03kN @ 21.2mm of thread in CF8m
Ultimate tensile load of bolt = UTS * At
800 * 156.67mm = 125Kn
Max tensile load of bolt = UYS * At
600*156.67 = 94Kn
Pressure is 240 bar= 24Mpa
Pcd Of bolts = 170 mm
diameter of hole in bolted flange = 80 mm
Therefore
Area of pressure = (Pi (Pcd+bolt diamter/2)^2 - Pi(80/2)^2)
Area of pressure = 22145mm
Force = Area of pressure x Pressure
= 22145mm * 24 Mpa
Force on flange = 531.5Kn
Min number of bolts = Force on flange / Max tensile load of bolt
= 531.5Kn/ 94Kn =5.6 bolts
Bolts with a Safety factor of 2 = Force on flange / (Max tensile load of bolt/2)
= 531.5Kn/ (94Kn/2) =11.3 bolts
Therefore I would need 12 bolts
Is the Flange is CF8m and 25mm long and the bolt is 55mm long and it an groove o-ring joint? what the stiffness factor of the joint?
My calcs say C is 0.9 but i think that is off by a large margin!!
Does any one have an worked example to calculate C for a tapped and flange or a studded assembly.
Bolt M16 A4-80 55mm long no shank
UTS = 800Mpa (not sure of)
UYS = 600Mpa (not sure of)
Shear ratio is 0.75 (not sure if it should be 0.7)
UTSh * 0.75 = 600Mpa
Stress Area of bolt = 156.67mm calculated
Tapped hole CF8M cast 30mm
UTS = 485MPa (known data)
UYS = 205MPa (known data)
Shear ratio =0 .75 (not sure about ratio)
UTS * 0.75
UTSh = 363.75Mpa
Minimum Length Of engagement = UTSh of bolt *0.8* Normal diameterof bolt/UTsh of tapped hole
= 600*0.8*16/363.75 = 21.2mm
Nasa Pull out load of thread
Pullout load = pi()*Min Minor diameter of thread *UTShtapped hole* Length of engagement/3
Min Minor diamet of thread = 13.872mm
= pi()*13.872*363.75* 21.2mm/3
Pullout load =112.03kN @ 21.2mm of thread in CF8m
Ultimate tensile load of bolt = UTS * At
800 * 156.67mm = 125Kn
Max tensile load of bolt = UYS * At
600*156.67 = 94Kn
Pressure is 240 bar= 24Mpa
Pcd Of bolts = 170 mm
diameter of hole in bolted flange = 80 mm
Therefore
Area of pressure = (Pi (Pcd+bolt diamter/2)^2 - Pi(80/2)^2)
Area of pressure = 22145mm
Force = Area of pressure x Pressure
= 22145mm * 24 Mpa
Force on flange = 531.5Kn
Min number of bolts = Force on flange / Max tensile load of bolt
= 531.5Kn/ 94Kn =5.6 bolts
Bolts with a Safety factor of 2 = Force on flange / (Max tensile load of bolt/2)
= 531.5Kn/ (94Kn/2) =11.3 bolts
Therefore I would need 12 bolts
Is the Flange is CF8m and 25mm long and the bolt is 55mm long and it an groove o-ring joint? what the stiffness factor of the joint?
My calcs say C is 0.9 but i think that is off by a large margin!!
Does any one have an worked example to calculate C for a tapped and flange or a studded assembly.