Carlloss
Mechanical
- Feb 20, 2012
- 21
Hi all,
Apologise if I refresh old questions however I have been looking for similar threads last few nights and could not find anything that would answer my questions. This is my first job as a design engineer and unfortunately I am on my own in entire company so it is imposable to consult my toughs with anybody. Basically I have application (dome pressure regulator, ref to attachment)and I am struggling to get correct pattern for thread calculation.The pressure regulator have threaded bonnet that is tighten against body thread M40 x 1.5. I have been ask will be possible to redesign this bonnet to dome application with 300bar inlet. Below I put step by step my calculation (also attached). I would be highly appreciated for any comets and suggestions especial that is my first thread.
Inputs:
Bonnet/body material: SS316 UTY=205 MPa; UTS=515 Mpa
Sealing diam. = 27mm
Pressure = 300bar (30Mpa)
Thread size = M40x1.5
Torque = ?
Engagement length = ?
Outputs:
1. I have calculated force acting against bonnet. I used sealing dim. behind the O' ring as a worst case scenario.
D=27mm
A=572,55 mm sq.
F=PA
F=17176,5 N
2.I have multiply this force by safety factor 1.3 to be sure that after pressure been applied I still have compression on O' ring
[F][/1]= 1,3xF= 17176,5 N
3.I try to check if M40x1.5 is sufficient for above inputs.
a) Thread can be stressed to 75% of material yield (I used 75% as I saw something similar in some book but I am unsure what is the best practise, plus what should I used UTY or UTS?)
sigma = 075xUTY = 153, 75 MPa
b) Calculated rqu. tensile stress area.
[A][/t1]= [F][/1]/sigma = 145, 23 mm sq.
c) Calculated tensil stress area for M40x1.5
[A][/t2]= Pi/4 ( D-0,938194xP) sq = 1100,74 mm sq.
4. Required torque to overcome F1.
T=KDP
T=0,15x0,044x22329,45= 147,3 round up to 148Nm
5.Length of engagement.
PDnom =PDmax + PDmin / 2 = 39,219mm
[L][/e]= 4[A][/t1] / Pi PDnom = 35,73mm
My questions are:
1. Does my calculations make any sense? Are they even correct?
2. Can I use shorter length of engagement as I can not change thread type, this must stay M40x1.5? If yes how to evaluate minimum length that wont cause any issue?
I would like to apologise also for any grammar/spelling mistakes as English is not my native language. Thank you in advance for your help.
Karol
Apologise if I refresh old questions however I have been looking for similar threads last few nights and could not find anything that would answer my questions. This is my first job as a design engineer and unfortunately I am on my own in entire company so it is imposable to consult my toughs with anybody. Basically I have application (dome pressure regulator, ref to attachment)and I am struggling to get correct pattern for thread calculation.The pressure regulator have threaded bonnet that is tighten against body thread M40 x 1.5. I have been ask will be possible to redesign this bonnet to dome application with 300bar inlet. Below I put step by step my calculation (also attached). I would be highly appreciated for any comets and suggestions especial that is my first thread.
Inputs:
Bonnet/body material: SS316 UTY=205 MPa; UTS=515 Mpa
Sealing diam. = 27mm
Pressure = 300bar (30Mpa)
Thread size = M40x1.5
Torque = ?
Engagement length = ?
Outputs:
1. I have calculated force acting against bonnet. I used sealing dim. behind the O' ring as a worst case scenario.
D=27mm
A=572,55 mm sq.
F=PA
F=17176,5 N
2.I have multiply this force by safety factor 1.3 to be sure that after pressure been applied I still have compression on O' ring
[F][/1]= 1,3xF= 17176,5 N
3.I try to check if M40x1.5 is sufficient for above inputs.
a) Thread can be stressed to 75% of material yield (I used 75% as I saw something similar in some book but I am unsure what is the best practise, plus what should I used UTY or UTS?)
sigma = 075xUTY = 153, 75 MPa
b) Calculated rqu. tensile stress area.
[A][/t1]= [F][/1]/sigma = 145, 23 mm sq.
c) Calculated tensil stress area for M40x1.5
[A][/t2]= Pi/4 ( D-0,938194xP) sq = 1100,74 mm sq.
4. Required torque to overcome F1.
T=KDP
T=0,15x0,044x22329,45= 147,3 round up to 148Nm
5.Length of engagement.
PDnom =PDmax + PDmin / 2 = 39,219mm
[L][/e]= 4[A][/t1] / Pi PDnom = 35,73mm
My questions are:
1. Does my calculations make any sense? Are they even correct?
2. Can I use shorter length of engagement as I can not change thread type, this must stay M40x1.5? If yes how to evaluate minimum length that wont cause any issue?
I would like to apologise also for any grammar/spelling mistakes as English is not my native language. Thank you in advance for your help.
Karol