novis76
Nuclear
- Feb 2, 2011
- 11
Hello, I doing a thermal expansion analysis on a nitrogen supply line for a expansion tank. I am doing two calculations. One in hot conditions and one in cold conditions. The hot temperature is known and is no problem. The problem is the cold case.
The system consists of a nitrogen tank of approx. 6 bar(a) / 10 deg C. After this there is a valve that is followed by a DN100 outlet pipe that connects to the expansion tank. If the valve is fully open and the expansion tank exit valve (large compared to the first valve) is also fully opened the first valve is choked and there is a flow of approx. 1.78 kg/s through the pipes (valve = ball valve is approximated with nozzle of D=40mm). Assuming neglible pressure loss in the outlet part this corresponds to about 189.83 m/s. With no change in total temperature the static temperature in the pipe should be
(273.15 + 10) - 189.83^2/ (2 * 1041) = 265.84 K = -7.31 deg C
My first thought was to use this temperature. However then I came across this page
that says that the temperature on the surface will be heated up due to the no slip (aerodynamic heating) of the surface to almost the total temperature (recovery factor = 0.89). My intuition says that i should use the static temperature (cold) but I am not sure. Can somebody please help me? Should I use the static temperature or the total temperature in my calculations?
Thanks
The system consists of a nitrogen tank of approx. 6 bar(a) / 10 deg C. After this there is a valve that is followed by a DN100 outlet pipe that connects to the expansion tank. If the valve is fully open and the expansion tank exit valve (large compared to the first valve) is also fully opened the first valve is choked and there is a flow of approx. 1.78 kg/s through the pipes (valve = ball valve is approximated with nozzle of D=40mm). Assuming neglible pressure loss in the outlet part this corresponds to about 189.83 m/s. With no change in total temperature the static temperature in the pipe should be
(273.15 + 10) - 189.83^2/ (2 * 1041) = 265.84 K = -7.31 deg C
My first thought was to use this temperature. However then I came across this page
that says that the temperature on the surface will be heated up due to the no slip (aerodynamic heating) of the surface to almost the total temperature (recovery factor = 0.89). My intuition says that i should use the static temperature (cold) but I am not sure. Can somebody please help me? Should I use the static temperature or the total temperature in my calculations?
Thanks