vpl
Nuclear
- Feb 4, 2002
- 1,929
I figured this might be the best place for this as, even though it's a work-related question, I'm not an electrical engineer.
I'm reviewing a document that seems to be mixing KVARs, ohms and watts. The person who wrote it is a good electrical engineer, but not a native English speaker. I'm not well-enough versed in "electrical" to make sure I'm "translating" correctly.
The paragraph that I'm currently scratching my head over reads: "The calculation concluded that maximum grounding resistor value of 4.225 ohms was required to provide the required KW loss equal to or greater than the charging KVAR and therefore, the installed resistor value of 4.2 ohms was adequately sized to protect the components from damage. This only provided a 0.025 ohms margin which allowed excess charging of 0.025 KVAR. The calculation results were based upon using the cabling and circuits for component-11 which showed that the calculated charging KVAR value was 4.545 and the resistor KW loss for the 4.2 ohms resistor was 4.57."
I've read this paragraph several time and keep coming to the conclusion that KVARs are being subtracted from KWs to get ohms. I speak enough "electrical" to know that's not right.
So the question is does this make sense to you electricals? Is it just happenstance that the resistor margin (0.025 ohms) is equivalent to the excess charging(0.025 KVAR)? Is the 4.57 loss in the last sentence in KW or KVAR?
Thanks!
Patricia Lougheed
******
Please see FAQ731-376: Eng-Tips.com Forum Policies for tips on how to make the best use of the Eng-Tips Forums.
I'm reviewing a document that seems to be mixing KVARs, ohms and watts. The person who wrote it is a good electrical engineer, but not a native English speaker. I'm not well-enough versed in "electrical" to make sure I'm "translating" correctly.
The paragraph that I'm currently scratching my head over reads: "The calculation concluded that maximum grounding resistor value of 4.225 ohms was required to provide the required KW loss equal to or greater than the charging KVAR and therefore, the installed resistor value of 4.2 ohms was adequately sized to protect the components from damage. This only provided a 0.025 ohms margin which allowed excess charging of 0.025 KVAR. The calculation results were based upon using the cabling and circuits for component-11 which showed that the calculated charging KVAR value was 4.545 and the resistor KW loss for the 4.2 ohms resistor was 4.57."
I've read this paragraph several time and keep coming to the conclusion that KVARs are being subtracted from KWs to get ohms. I speak enough "electrical" to know that's not right.
So the question is does this make sense to you electricals? Is it just happenstance that the resistor margin (0.025 ohms) is equivalent to the excess charging(0.025 KVAR)? Is the 4.57 loss in the last sentence in KW or KVAR?
Thanks!
Patricia Lougheed
******
Please see FAQ731-376: Eng-Tips.com Forum Policies for tips on how to make the best use of the Eng-Tips Forums.