Eng-Tips is the largest engineering community on the Internet

Intelligent Work Forums for Engineering Professionals

  • Congratulations waross on being selected by the Tek-Tips community for having the most helpful posts in the forums last week. Way to Go!

Trivial question on head loss conversion.

Status
Not open for further replies.

dbecker

Mechanical
Dec 16, 2008
138
0
0
US
I am trying to convert head loss of feet into corresponding pressure drop in psi.

If I multiply the height in feet by density which is in units of lbm/ft^3, then my result will not be pounds force per square foot, but pounds mass per square foot (this is not pressure!!!).

Am I missing something here?

Thanks
 
Replies continue below

Recommended for you

Maybe this is obvious to everyone else, but it helps me to remember that the reason the 'customary pound' units are the way they are is this: normally (ie, here on the surface of the earth) a pound mass weighs a pound (force). The problem is, if you apply a force of 1 lbf to a mass of 1 lbm, it does not accelerate at 1 ft/sec2; in fact it accelerates at 32.2 ft/sec2.

That's really the source of all (my) confusion, and the reasons why the units are set up to confuse me. Like I said, understanding that helps me put the 32.2 in where it goes.
 
Actually that depends in which direction the force is applied and acceleration would be 33.2 ft/sec, if the force was applied downward not 32.2.

**********************
"Pumping accounts for 20% of the world’s energy used by electric motors and 25-50% of the total electrical energy usage in certain industrial facilities."-DOE statistic (Note: Make that 99% for pipeline companies)
 
Status
Not open for further replies.
Back
Top