1. You are assuming a 0.6 M limit as 0.6 Mach for the pressure, temperature and flow at the inlet of the tube, middle (approximately) of the 9 mm ID tube, or the location right at the little hole in the tube wall?
(Not 0.6 Mach for the gas after it leaves the tube wall hole, right? (Cooling only happens in the expansion region outside of the tube, as i understand the OP's problem and assumptions.)
2. The OP has two contradictions: If the gas is flowing through such a little tube at a (assumed ??) gas pressure of 150 psi (assumed GAGE pressure - and why is he switching units ???) , then it MUST be constantly resupplied at the tube inlet from a gas main or large chamber. If so, then the flow will rapidly stabilize so the inlet pressure remains 150 psig, and the outlet pressure after an UNKNOWN length of tube = 150 psig - flow losses through tube to the halfway (???) point at 100% flow - PVnRT mass losses through the side diversion of the 1 mm hole - flow losses of the remaining gasses through the remainder of the tube - exit losses when the remaining gasses leave the 9mm ID tube at whatever condition they originally were facing.
It appears you're using a simple variety of this constant flow assumption: The flow is from a near-constant 150 psig (at centerline of the tube at radius 0.0) through the inlet flow losses at the wall at 4.5 mm radius, through the 1.5 mm thick wall hole 1.0 mm dia, through the exit losses at the outside tube wall, then against atmospheric pressure.
None of which are stated in this apparent homework problem. 8<(
3. Now, IF BOTH end of the tube were isolated immediately when the leak occurred, then the end psig = 0.0 because the 9 mm ID tube will be "empty" of gas after 1 hour. The volume of gas lost = initial volume of the tube (@ PVnRT mass conditions at 164.7 psia) minus final volume of the gas (@ PVnRT conditions at 14.7 psia)
4. Assume the tube is isolated at the inlet. Then the final pressure will approximate the outlet pressure of the reciever or reservoir or tank if it is above atmospheric pressure, again minus flow losses from the final pressure in the unknown length of tubing from the end to the leak point.