rgspringer
Geotechnical
- Feb 11, 2010
- 3
As part of a slope stability analysis, we performed field vane shear tests on lean clay soils (PI between 10 and 22) using a Geonor H-70. The vane shear testing was performed as a supplement to previous testing performed on Shelby tube samples which yielded lower than expected results, possibly due to disturbance of the more sensitive, saturated materials.
The vane shear device did not have a "torque" ouput, but instead, the device output was already calibrated to provide the undrained shear strength, in kPa. The test results were reduced using the correction factor suggested by Azzouz in the Journal of Geotechncial Engineering, Vol. 109, No. 5, May 1983.
My first question is how do you break down the undrained shear strength of the unsaturated materials into a cohesion and phi value? I estimated a phi based on the PI and then roughly tried to back calculate the cohesion using the following equation: c = su -(po * 0.618 *tan (phi))
where: c = cohesion
su = field vane undrained shear strength
po = at rest lateral earth pressure
phi = drained angle of internal friction
0.618 = circumference of the field vane
Is this approach reasonable?
Secondly, for the saturated clay materials, typically, phi = 0; therefore, su = c. So can I assume that the field vane shear strengths are equal to the cohesion? The problem I am having with this is that the soils in this area have been shown to be normally consolidated to slightly overconsolidated (OCR = 1 to 1.1) based on consolidation testing. For normally consolidated soils, typically, su = 0.2 * pv', where pv' is the effective overburden pressure. Based on this correlation, my undrained shear strength for the saturated clays should be on the magnitude of about 600 psf; however, I'm getting vane shear values as much as 500 psf higher than this.
Any help would be greatly appreciated. Thanks.
The vane shear device did not have a "torque" ouput, but instead, the device output was already calibrated to provide the undrained shear strength, in kPa. The test results were reduced using the correction factor suggested by Azzouz in the Journal of Geotechncial Engineering, Vol. 109, No. 5, May 1983.
My first question is how do you break down the undrained shear strength of the unsaturated materials into a cohesion and phi value? I estimated a phi based on the PI and then roughly tried to back calculate the cohesion using the following equation: c = su -(po * 0.618 *tan (phi))
where: c = cohesion
su = field vane undrained shear strength
po = at rest lateral earth pressure
phi = drained angle of internal friction
0.618 = circumference of the field vane
Is this approach reasonable?
Secondly, for the saturated clay materials, typically, phi = 0; therefore, su = c. So can I assume that the field vane shear strengths are equal to the cohesion? The problem I am having with this is that the soils in this area have been shown to be normally consolidated to slightly overconsolidated (OCR = 1 to 1.1) based on consolidation testing. For normally consolidated soils, typically, su = 0.2 * pv', where pv' is the effective overburden pressure. Based on this correlation, my undrained shear strength for the saturated clays should be on the magnitude of about 600 psf; however, I'm getting vane shear values as much as 500 psf higher than this.
Any help would be greatly appreciated. Thanks.