Eng-Tips is the largest engineering community on the Internet

Intelligent Work Forums for Engineering Professionals

Verify Results 2

Status
Not open for further replies.

stilkikin

Mechanical
Dec 30, 2023
7
0
0
AU
Hi All,

Could you please check my calculations to see if I have this correct, it's been a while & need to check.

Stress in Flywheel
4140 Steel
Tensile strength 655 MPa 95000 psi
Yield strength 415 MPa 60200 psi

σt-max = d/4 * w^2 * ( 3+ v * R2^2 + (1-v) * R1^2

σt-max is the maximum internal stress in the flywheel N/m^2

d is the density of the flywheel material Kg/m^3

ω is the angular velocity of the flywheel rad/sec

v is the Poisson ratio of the flywheel material-Steel

The Factor of safety FOS can be calculated as

FOS = σ-yield / σt-max

Where

(σ yield) is the possible angular velocity when the maximum internal stress equals the yield stress of the material.

Flwheel Diam R2 = 0.15 radius mtrs

Flywheel inner dia R1 = 0.025 radius mtrs

Density of steel = 7850 Kg/m^3

Tensile strength = 655 Mpa

Pa = 655000000 Pascals

Poisson's ratio (v) = 0.3

ω max = 1571 rad/sec

Velocity = 235.65 m/s

rpm max = 15000

σt-max = d/4 * w^2 * ( 3+ v * R2^2 + (1-v) * R1^2

d/4 = 1962.5

ω^2 = 2468041

3+v = 3.3

R2^2 = 0.0225

1-v = 0.7

R1^2 = 0.000625

σt-max = 2343814.663 N/m^2

= 2.343814663 Mpa

FOS = σ yield / σt-max

= 415 Mpa / 2.343814663 Mpa

FOS = 177.0618 ??

The FOS appears to be very high do I have this correct?
 
Replies continue below

Recommended for you

your brackets don't balance. I suspect you're missing three ... ( (3+ v) * R2^2 + (1-v) * R1^2 )

"Hoffen wir mal, dass alles gut geht !"
General Paulus, Nov 1942, outside Stalingrad after the launch of Operation Uranus.
 
stilkikin (Mechanical)(OP),

The units are not consistent .Apparently you are following SI units , the unit of density SHALL BE ( WT=Newton / 9.8) That is , 78500/9.81=
The answer should be in the range of 180 mPa.
Will you post the excerpt showing the formula?


Use it up, wear it out;
Make it do, or do without.

NEW ENGLAND MAXIM


 
HTURKAK,
The formula was from memory, which is fading obviously & why I need correction.
Not sure I follow what you are suggesting?
The SI units for solids-density are Kg/m^3 or g/cm^3 which would be 7850Kg/m^3 or 7.85g/cm^3

Could you give me an example to have a look at?
 
The following is excerpt from STANDARD HANDBOOK OF MACHINE DESIGN ( By E. Shigley , R. Mischke )

flywheel_stresses_1_kvb9de.jpg

flywheel_stresses_2_k8waqr.jpg


If we put your data to the expression (18.58)
σ0 = 78500*(0.15**2)*(1571**2)*(3+0.3)/(8*9.81) =183298744 N/m2 =183 MPa.

and the max. tangential stress would be around double of σ0. I think there are some typo mistake at your expression. If you post the original formula we can see the mistake. Regarding the density , i have used one more zero with typing mistake and corrected .



Use it up, wear it out;
Make it do, or do without.

NEW ENGLAND MAXIM
 
weight density (N/m3) divided by "g" is just mass density (kg/m3). dividing things by "g" is a sign of the imperial system. Maybe that equation assumes imperial units (ie weight density in lbf/in3) ?

"Hoffen wir mal, dass alles gut geht !"
General Paulus, Nov 1942, outside Stalingrad after the launch of Operation Uranus.
 
Rearranging my missing brackets as kindly suggested, I get the following.

4140 Steel
Tensile strength 655 MPa 95000 psi
Yield strength 415 MPa 60200 psi

Stress in Flywheel
σt-max = d/4 * w^2 *((3 + v) * R2^2 + (1-v) * R1)
σt-max = the maximum internal stress in the flywheel N/m^2
d = the density of the flywheel material Kg/m^3

ω = the angular velocity of the flywheel rad/sec
v = the Poisson ratio of the flywheel material 0.3
The Factor of safety FOS can be calculated as
FOS = σ yield / σt-max
Where
σ yield is the maximum possible angular velocity when the maximum internal stress equals the yield stress of the material.

Flwheel Diam R2 = 0.15 radius mtrs
Flywheel inner dia R1 = 0.025 radius mtrs
Density of steel = 7850 Kg/m^3
Tensile strength = 655 Mpa
Yield strength = 415 MPa
Poisson's ratio v = 0.3
ω = 1571 rad/sec
Velocity- Peripheral = 235.65 m/s
kph = 848
rpm max = 15000

σt-max = d/4 * ω^2 * ((3 + v) * R2^2 + (1-v) * R1)

= 1962.5 * 2468041 *(( 3.3 ) * 0.0225 + (0.7) * 0.025)

= 4,843,530,462.5 * 0.07425 + 0.0175

= 4,843,530,462.5 * 0.09175
= 444,393,919.9 N/m^2
= 444.4 MPa

FOS = σ yield / σt-max
415 MPa / 444.5 MPa
= 0.933 = DANGER ?
 
Status
Not open for further replies.
Back
Top