dspfun
Electrical
- Feb 2, 2003
- 4
How does someone consider a voltage drop for long runs of an outdoor receptacle circuit? The NEC shown below says you need 3% maximum voltage in your feeder. I've been given two different approaches to this and would like the opinion of this forum. One engineer has told me he just uses #10 wires and doesn't calculate anything.
Another told me to use the demand for a typical outlet (180w @120v = 1.5a) and calculate the voltage drop for each leg and sum it up.
For example:
A 5 outlet circuit w/ 250ft to first outlet 7.5a total with the remaining four circuits having 75ft between them you calculate the voltage drop for each leg and sum it up and design for 3% max total.
(VD%=2*250ft*7.5a*0.51ohm/kft/1000ft/kft*100%=1.59%VD)
(VD%=2*75ft*6.0a*0.51ohm/kft/1000ft/kft*100%=0.38%VD)
(VD%=2*75ft*4.5*0.809ohm/kft/1000ft/kft*100%=0.46%VD)
(VD%=2*75ft*3.0a*0.809ohm/kft/1000ft/kft*100%=0.30%VD)
(VD%=2*75ft*1.5a*0.809ohm/kft/1000ft/kft*100%=0.15%VD)
total VD of 2.89%
Alternately:
Would you want to design the cable size considering the voltage drop with a max load of say 1.5kw (12.5A) plugged into the final receptacle (VD%=2*550ft*12.5a*0.201ohm/kft/1000ft/kft*100%=2.3%VD)
I would like to hear your thoughts on how to design for this situation.
Thanks,
CKB
The NEC says:
Conductors for branch circuits as defined on article 100, sized to prevent a voltage drop exceeding 3 percent at the farthest outlet of power, heating, and lighting loads, or combinations of such loads, and where maximum total voltage drop on both feeders and branch circuits to the farthest outlet does not exceed 5 percent.
(0.201ohm/kft #2, from Table in Chapter 9 NEC)
(0.51ohm/kft #6, from Table in Chapter 9 NEC)
(0.809ohm/kft #8, from Table in Chapter 9 NEC)
Another told me to use the demand for a typical outlet (180w @120v = 1.5a) and calculate the voltage drop for each leg and sum it up.
For example:
A 5 outlet circuit w/ 250ft to first outlet 7.5a total with the remaining four circuits having 75ft between them you calculate the voltage drop for each leg and sum it up and design for 3% max total.
(VD%=2*250ft*7.5a*0.51ohm/kft/1000ft/kft*100%=1.59%VD)
(VD%=2*75ft*6.0a*0.51ohm/kft/1000ft/kft*100%=0.38%VD)
(VD%=2*75ft*4.5*0.809ohm/kft/1000ft/kft*100%=0.46%VD)
(VD%=2*75ft*3.0a*0.809ohm/kft/1000ft/kft*100%=0.30%VD)
(VD%=2*75ft*1.5a*0.809ohm/kft/1000ft/kft*100%=0.15%VD)
total VD of 2.89%
Alternately:
Would you want to design the cable size considering the voltage drop with a max load of say 1.5kw (12.5A) plugged into the final receptacle (VD%=2*550ft*12.5a*0.201ohm/kft/1000ft/kft*100%=2.3%VD)
I would like to hear your thoughts on how to design for this situation.
Thanks,
CKB
The NEC says:
Conductors for branch circuits as defined on article 100, sized to prevent a voltage drop exceeding 3 percent at the farthest outlet of power, heating, and lighting loads, or combinations of such loads, and where maximum total voltage drop on both feeders and branch circuits to the farthest outlet does not exceed 5 percent.
(0.201ohm/kft #2, from Table in Chapter 9 NEC)
(0.51ohm/kft #6, from Table in Chapter 9 NEC)
(0.809ohm/kft #8, from Table in Chapter 9 NEC)