jordon
Electrical
- Oct 4, 2006
- 3
I'd like some guidance on how to measure 450VAC, 60Hz, and pass this to a low voltage sensing circuit (approx. 3 V going to a high-impedence ADC). The two circuits (450V and sensing) must be galvanically isolated.
1. The brute force approach would be to use a 450:3V transformer. The ADC will simply grab the voltage coming out of the transformer secondary. However, I've found that this transformer is rather large. I'd like the transformer to fit on a PCB, if possible.
2. Another approach is to use voltage divider with a 1:1 transformer. See attachment. We size the voltage divider resistors such that 3V forms across the transformer. However, two problems. 1) The resistors dissipate about 6W of power. I have to measure nine (9) voltages, so this adds up (9x6W=54W). 2) The voltage divider is directly proportional to the DC resistance of the transformer, which is in turn influenced by the ambient temperature. In other words, the hotter the environment, the higher the resistance.
3. I want to explore other alternatives. I've heard about linear optocouples or high-impedence Op-Amps sitting on the 450 V line, and draw virtually no power, but Op-Amps would require a power supply hanging on the 450 V line as well, and linear optocouples may lose linearity near the peaks and zero-crosses.
Basically, the goal is to design a voltage sensing circuit that doesn't vary with temperature (error < 1% from 0 to 80 C), does not dissipate more than, say, 1-2 Watts, and has a footprint small enough to fit on a PCB, say 3x3 in.
What's the best way to do this?
1. The brute force approach would be to use a 450:3V transformer. The ADC will simply grab the voltage coming out of the transformer secondary. However, I've found that this transformer is rather large. I'd like the transformer to fit on a PCB, if possible.
2. Another approach is to use voltage divider with a 1:1 transformer. See attachment. We size the voltage divider resistors such that 3V forms across the transformer. However, two problems. 1) The resistors dissipate about 6W of power. I have to measure nine (9) voltages, so this adds up (9x6W=54W). 2) The voltage divider is directly proportional to the DC resistance of the transformer, which is in turn influenced by the ambient temperature. In other words, the hotter the environment, the higher the resistance.
3. I want to explore other alternatives. I've heard about linear optocouples or high-impedence Op-Amps sitting on the 450 V line, and draw virtually no power, but Op-Amps would require a power supply hanging on the 450 V line as well, and linear optocouples may lose linearity near the peaks and zero-crosses.
Basically, the goal is to design a voltage sensing circuit that doesn't vary with temperature (error < 1% from 0 to 80 C), does not dissipate more than, say, 1-2 Watts, and has a footprint small enough to fit on a PCB, say 3x3 in.
What's the best way to do this?