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Volumetric flow calculation

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Sa-Ro

Industrial
Jul 15, 2019
273
Hi..

Can we calculate volumetric flow for given data:

Case 1:

Orifice diameter, mm = 5

Inlet pressure, Bar = 6

Pressure drop, Bar = 1

Medium: Compressed air

Case 2:

Orifice diameter, mm = 5

Inlet pressure, Bar = 6

Pressure drop, Bar = 0

Medium: Compressed air

Thank you.
 
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Yes. Here in Colorado I use 12.2psi for local atmospheric pressure.

Ted
 
LittleInch said:
at 6 barg is appro 8.4 kg/m3

How did you get this number?

Density for air: 1.29 Kg/m3

LittleInch said:
amend it to be the volumetric flow at standard conditions

I am unable to get your point.

Can you elaborate with numbers?

hydtools said:
1.013 bars. Bara=barg+1.013

Thank you

hydtools said:
Colorado I use 12.2psi for local atmospheric pressure

How did you get this number? or any formula to calculate?

Thanks with Regards,
Sathish Rosario
 
Sathish,

Please read the response carefully and do some research. Air density changes with pressure. Look it up. I use engineering toolbox.

When dealing with compressible fluids you either need to work with mass or correct everything to a standard condition otherwise you get confused between actual flow and standard flow.

Your 1000 litres of "free air" is essentially at standard conditions. The calculations are at actual conditions at a given pressure. Hence why there is so much difference.

Until you understand this you won't get very far.

Remember - More details = better answers
Also: If you get a response it's polite to respond to it.
 
LittleInch said:
do some research

Thank for the input.

Below are my observations.

Density is function of pressure and temperature.

Standard temperature and pressure: 15 degree Celsius and 101325 pa.

Normal temperature and pressure: 0 degree Celsius and 101325 pa.

[URL unfurl="true"]https://www.controlandinstrumentation.com/flow/standard.html[/url]

Air density at standard temperature and pressure: 1.225 Kg/m3.

Air density at normal temperature and pressure: 1.292 Kg/m3.

Since my upstream pressure is 6 barg = 7 bar absolute, we need to apply ideal gas law formula:

PV = mRT

Where,
P = Absolute pressure, pascal
V = Volume of substance, m3
m = mass, gram
R = Gas constant,
T = Absolute temperature, kelvin

[URL unfurl="true"]https://www.docbrown.info/page03/3_52gaslaws2.htm[/url]

Calculator: (still looking for step by step example)
[URL unfurl="true"]https://www.omnicalculator.com/physics/air-density[/url]

Arrived density at 6 barg = 8.4 kg/m3..

Rest of the things I will study and come back.

hydtools said:

Thank you.
 
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