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VUSDFLD and property definition

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loyal979

Mechanical
Nov 6, 2018
47
Hi all,

I have written a VUSDFLD ABAQUS user subroutine and I am just wondering on how to define material property based on the field variables. Could someone show me how to do that? and Should be the number of field variables be same as the number of failure modes? I have attached an image example to show what exactly I am talking about.
PropertyDefinition_uv7flj.jpg

Thanks in advance
Matt
 
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Abaqus uses the material property based on which value of the vield variable is closest to the actual result. In your case, the actual value of strain is compared to the value of your field variables. It checks which value in your table is closest to the strain value obtained. Once this value is found, the material properties are used which are specified in this same row of your table. For example, if the value of E11 is 0.05, abaqus uses the material properties of row 3 (since in this row a value of 0.05 is specified). Thus, for E1 a value iof 135.55 will be used. However, since your vield variables contain some identical values on several rows, this might give some errors. Also, if not an exact identicial value can be found in the list, I think abaqus uses interpolation (e.g. if you only provided data for if E11=0.01 and E11=0.03, while the actual E11=0.02, a interpolated value is used between the values of these rows).
 
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