mielke
Mechanical
- Aug 24, 2009
- 181
I am familiar with an equation that gives me the kilograms of water vapor in air, which is...
water vapor(kg)=air(kg)*relative humidity/100*Sat. Pressure of water/Operating Pressure*MoleWeight of water/MoleWeight of air.
I am pretty confident in this equation but lets say for example I have 66.6% RH at 25C, with an operating pressure of 0.101MPa and a Sat Pressure of 0.00317MPa and if I have 100kg of air then I should have 1.3kg of water vapor in my air (according to the above equation).
But when I look at the properties for water at 0.101MPa and 25C obviously water is in the liquid state. And if the air is at 25C then shouldn't it condense any water in the air?
I am just hoping for any insight into the appearant confusion I have.
Thank You
water vapor(kg)=air(kg)*relative humidity/100*Sat. Pressure of water/Operating Pressure*MoleWeight of water/MoleWeight of air.
I am pretty confident in this equation but lets say for example I have 66.6% RH at 25C, with an operating pressure of 0.101MPa and a Sat Pressure of 0.00317MPa and if I have 100kg of air then I should have 1.3kg of water vapor in my air (according to the above equation).
But when I look at the properties for water at 0.101MPa and 25C obviously water is in the liquid state. And if the air is at 25C then shouldn't it condense any water in the air?
I am just hoping for any insight into the appearant confusion I have.
Thank You